Morphocompletion for #3064 ⟨a, b | aabababaaba=1⟩

Solved by morph:2/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaab ⇒ baabaa
2. aababab ⇒ babaaba
3. abababaaba ⇒ bababaabaa
4. baabaaaaab ⇒ abaabaabaa
5. bababaabaaa ⇒ 1
6. babaabaaaab ⇒ aababbaabaa
7. baaababbaabaa ⇒ ab
8. baaababbabaabaa ⇒ abab
9. bbaaababbabaabaa ⇒ babab
10. abababaabbabaaba ⇒ babab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] baa, [3/2] aab, [3/3] bab
Length 4:[4/0] abaa, [4/1] aaba, [4/2] abab, [4/3] baba
Length 5:[5/0] baaba, [5/1] aabaa, [5/2] ababa, [5/3] babaa
Length 6:[6/0] baabaa, [6/1] babaab, [6/2] abaaba, [6/3] ababab

Considering [length 2 / frequency 0] ba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ccccaca ⇒ b
2. acccac ⇒ cccaca
3. cacccac ⇒ b
4. aaccc ⇒ ccaca
5. ba ⇒ c
6. caccb ⇒ bccac
7. cccacaa ⇒ 1
8. acaac ⇒ cacaa
9. bccaca ⇒ caccc
10. bcaacc ⇒ cccca
11. ccaab ⇒ bcaca
12. ccaacb ⇒ caccc
13. aaccb ⇒ ccac
14. bcacaa ⇒ ccaac
15. acaab ⇒ caca
16. bcaacb ⇒ cccc
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ac, [2/1] cc, [2/2] ca, [2/3] aa, [2/4] bc, [2/5] cb, [2/6] ab
Length 3:[3/0] cac, [3/1] aca, [3/2] caa, [3/3] aac, [3/4] cca, [3/5] ccc, [3/6] acc
Length 4:[4/0] acaa, [4/1] ccac, [4/2] aacc, [4/3] caca, [4/4] caac, [4/5] accc, [4/6] ccca
Length 5:[5/0] cccac, [5/1] ccaca, [5/2] caacb, [5/3] bcaac, [5/4] cacaa, [5/5] accca, [5/6] bcaca

Considering [length 4 / frequency 0] acaa=d.

Step 3

Rewriting system is complete. See a, b | aabababaaba=1⟩.