Morphocompletion for #3063 ⟨a, b | aabababaaab=1⟩

Solved by morph:2/0,4/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaab ⇒ baaaba
2. abababa ⇒ babaaab
3. abaabab ⇒ bababaa
4. aabbaaaba ⇒ baaabaaab
5. bababaaabaa ⇒ 1
6. abbabaaab ⇒ babaaabba
7. ababaaabbaa ⇒ baaabaaabab
8. ababbababaa ⇒ babaaababab
9. bababaaababaaaba ⇒ abaab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] aab, [3/3] baa
Length 4:[4/0] baba, [4/1] abab, [4/2] abaa, [4/3] aaba
Length 5:[5/0] ababa, [5/1] baaab, [5/2] babaa, [5/3] babab
Length 6:[6/0] bababa, [6/1] ababaa, [6/2] abaaab, [6/3] baaaba

Considering [length 2 / frequency 0] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. caccca ⇒ acaccc
2. ccaac ⇒ accca
3. cccaa ⇒ acacc
4. aacaccc ⇒ 1
5. acaccca ⇒ 1
6. acccaa ⇒ aacacc
7. caaca ⇒ aacac
8. aaacaccc ⇒ a
9. ccaaaccca ⇒ acccacaac
10. aacacacacc ⇒ caa
11. aacacacaccc ⇒ caac
12. aacaccacacc ⇒ ccaa
13. b ⇒ acacccc
14. ab ⇒ c
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] cc, [2/1] ca, [2/2] ac, [2/3] aa
Length 3:[3/0] aca, [3/1] cac, [3/2] aac, [3/3] cca, [3/4] acc, [3/5] ccc, [3/6] caa
Length 4:[4/0] acac, [4/1] aaca, [4/2] cacc, [4/3] accc, [4/4] ccca, [4/5] ccaa, [4/6] caca
Length 5:[5/0] acacc, [5/1] aacac, [5/2] caccc, [5/3] accca, [5/4] cacac, [5/5] acaca, [5/6] aaaca

Considering [length 4 / frequency 1] aaca=d.

Step 3

Rewriting system is complete. See a, b | aabababaaab=1⟩.