Morphocompletion for #3056 ⟨a, b | aababaaabba=1⟩

Back:⟨a, b | aababaaabba=1⟩

Solved by morph:5/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaaab ⇒ baaaaa
2. abaaab ⇒ baaaba
3. abbaaabaaa ⇒ baaabaaaab
4. aabbaaab ⇒ baaabbaa
5. aabbaaaba ⇒ baaabbaaa
6. bbaaababaaa ⇒ 1
7. abbaaabab ⇒ bbaaababa
8. bbaaababbaaaaa ⇒ aab
9. bbaaabababaaaaa ⇒ aaab
10. bbaaababaabaaaaa ⇒ aaaab
11. bbaaababbbaaaaa ⇒ aabb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aaa, [3/1] aab, [3/2] baa, [3/3] bba, [3/4] aba, [3/5] abb, [3/6] bab
Length 4:[4/0] baaa, [4/1] bbaa, [4/2] aaaa, [4/3] aaab, [4/4] aaba, [4/5] abab, [4/6] abba
Length 5:[5/0] bbaaa, [5/1] baaab, [5/2] aaaaa, [5/3] aaaba, [5/4] abaaa, [5/5] aabab, [5/6] abbaa
Length 6:[6/0] bbaaab, [6/1] baaaba, [6/2] baaaaa, [6/3] aaabab, [6/4] abbaaa, [6/5] aabbaa, [6/6] aababa
Length 7:[7/0] bbaaaba, [7/1] abbaaab, [7/2] baaabab, [7/3] aabbaaa, [7/4] bbaaaaa, [7/5] abaaaaa, [7/6] aaababa

Considering [length 5 / frequency 1] baaab=c.

Step 2

Rewriting system is complete. See ⟨a, b | aababaaabba=1⟩.