Certificate for #3055 ⟨a, b | aababaaabab=1⟩

Completion settings:

[1] aababaaabab=1

Axiom: aababaaabab=1.

Referenced by [3].

[2] abab=c

Axiom: abab=c.

Referenced by [3], [5], [9].

[3] acaac=1

Overlap of [1] aababaaabab=1 with [2] abab=c:

a ababaaabab abab

Critical pair: acaaabab=1.

Reduce LHS:

[2]acaa(abab)
acaac

Referenced by [4], [6], [8], [11].

[4] aca=aac

Overlap of [3] acaac=1 with [3] acaac=1:

aca ac acaac

Critical pair: aca=aac.

Referenced by [6], [7], [11], [12].

[5] cab=abc

Overlap of [2] abab=c with [2] abab=c:

ab ab abab

Critical pair: abc=cab.

Flip LHS and RHS.

Referenced by [10].

[6] aaacc=1

Overlap of [3] acaac=1 with [4] aca=aac:

acaac aca

Critical pair: aacac=1.

Reduce LHS:

[4]a(aca)c
aaacc

Defines rule #2.

Referenced by [7], [15].

[7] aacca=1

Overlap of [4] aca=aac with [4] aca=aac:

ac a aca

Critical pair: acaac=aacca.

Reduce LHS:

[4](aca)ac
[4]a(aca)c
[6](aaacc)
⇒ 1

Flip LHS and RHS.

Referenced by [8], [9].

[8] ca=ac

Overlap of [3] acaac=1 with [7] aacca=1:

ac aac aacca

Critical pair: ac=ca.

Flip LHS and RHS.

Defines rule #1.

Referenced by [10], [12], [13], [14], [15].

[9] bab=aaccc

Overlap of [7] aacca=1 with [2] abab=c:

aacc a abab

Critical pair: aaccc=bab.

Flip LHS and RHS.

Defines rule #5.

[10] acb=abc

Simplify [5] cab=abc.

Reduce LHS:

[8](ca)b
acb

Referenced by [11], [12].

[11] aaabcc=b

Overlap of [3] acaac=1 with [10] acb=abc:

aca ac acb

Critical pair: acaabc=b.

Reduce LHS:

[4](aca)abc
[4]a(aca)bc
[10]aa(acb)c
aaabcc

Referenced by [12], [13].

[12] cb=bc

Overlap of [8] ca=ac with [11] aaabcc=b:

c a aaabcc

Critical pair: cb=acaabcc.

Reduce RHS:

[4](aca)abcc
[4]a(aca)bcc
[10]aa(acb)cc
[11](aaabcc)c
bc

Defines rule #3.

[13] aaabacc=ba

Overlap of [11] aaabcc=b with [8] ca=ac:

aaabc c ca

Critical pair: aaabcac=ba.

Reduce LHS:

[8]aaab(ca)c
aaabacc

Referenced by [14].

[14] aaabaacc=baa

Overlap of [13] aaabacc=ba with [8] ca=ac:

aaabac c ca

Critical pair: aaabacac=baa.

Reduce LHS:

[8]aaaba(ca)c
aaabaacc

Referenced by [15].

[15] aaab=baaa

Overlap of [14] aaabaacc=baa with [8] ca=ac:

aaabaac c ca

Critical pair: aaabaacac=baaa.

Reduce LHS:

[8]aaabaa(ca)c
[6]aaab(aaacc)
aaab

Defines rule #4.