| Back: | ⟨a, b | aabaabbabba=1⟩ |
|---|
Solved by morph:6/0,5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | baabbabba ⇒ abaabbabb |
| 2. | babbaaab ⇒ aabbabba |
| 3. | bbabbaaa ⇒ abaabbab |
| 4. | bbaaabaa ⇒ aabaabba |
| 5. | aaabaabbabb ⇒ 1 |
| 6. | baaabaabba ⇒ aaabaabbab |
| 7. | baabbababaabbabb ⇒ aabaabbabbbbabba |
| 8. | baabbabaabaabbabb ⇒ aabaabbabbbbabbaa |
| 9. | aaabaabbababaabbab ⇒ babbaaa |
| 10. | aaabaabbabaabaabba ⇒ baaabaa |
| ... |
Collecting factors up to length 7, frequency 4:
| Length 2: | [2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb |
|---|---|
| Length 3: | [3/0] baa, [3/1] bba, [3/2] aab, [3/3] abb |
| Length 4: | [4/0] abba, [4/1] baab, [4/2] abaa, [4/3] bbab |
| Length 5: | [5/0] baabb, [5/1] aabba, [5/2] abaab, [5/3] abbab |
| Length 6: | [6/0] baabba, [6/1] aabbab, [6/2] aaabaa, [6/3] abaabb |
Considering [length 6 / frequency 0] baabba=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | cacbc ⇒ acbb |
| 2. | ccacbc ⇒ cacbb |
| 3. | bba ⇒ acbc |
| 4. | acacbc ⇒ aacbb |
| 5. | acbccacbc ⇒ acbcacbb |
| 6. | cacbacbb ⇒ aacbbcbc |
| 7. | baabc ⇒ caacbc |
| 8. | baabb ⇒ caacbb |
| 9. | bcaacbc ⇒ acbcabc |
| 10. | bcaacbb ⇒ acbcabb |
| 11. | aaacbb ⇒ 1 |
| 12. | aacbbcacbc ⇒ cbb |
| 13. | baaacb ⇒ 1 |
| 14. | baaacbc ⇒ c |
| 15. | aaacbacbc ⇒ ba |
| 16. | baaacbacbb ⇒ acbb |
| 17. | baaacbaacbb ⇒ aacbb |
| ... |
Collecting factors up to length 6, frequency 7:
| Length 2: | [2/0] bc, [2/1] ac, [2/2] aa, [2/3] cb, [2/4] ba, [2/5] bb, [2/6] ca |
|---|---|
| Length 3: | [3/0] acb, [3/1] cbc, [3/2] baa, [3/3] aac, [3/4] cbb, [3/5] aaa, [3/6] cac |
| Length 4: | [4/0] acbc, [4/1] aacb, [4/2] acbb, [4/3] baaa, [4/4] aaac, [4/5] cacb, [4/6] bcaa |
| Length 5: | [5/0] aaacb, [5/1] baaac, [5/2] aacbb, [5/3] cacbc, [5/4] bcaac, [5/5] aacbc, [5/6] bacbb |
Considering [length 5 / frequency 0] aaacb=d.
Rewriting system is complete. See ⟨a, b | aabaabbabba=1⟩.