Morphocompletion for #3046 ⟨a, b | aabaabbabba=1⟩

Solved by morph:6/0,5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. baabbabba ⇒ abaabbabb
2. babbaaab ⇒ aabbabba
3. bbabbaaa ⇒ abaabbab
4. bbaaabaa ⇒ aabaabba
5. aaabaabbabb ⇒ 1
6. baaabaabba ⇒ aaabaabbab
7. baabbababaabbabb ⇒ aabaabbabbbbabba
8. baabbabaabaabbabb ⇒ aabaabbabbbbabbaa
9. aaabaabbababaabbab ⇒ babbaaa
10. aaabaabbabaabaabba ⇒ baaabaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] baa, [3/1] bba, [3/2] aab, [3/3] abb
Length 4:[4/0] abba, [4/1] baab, [4/2] abaa, [4/3] bbab
Length 5:[5/0] baabb, [5/1] aabba, [5/2] abaab, [5/3] abbab
Length 6:[6/0] baabba, [6/1] aabbab, [6/2] aaabaa, [6/3] abaabb

Considering [length 6 / frequency 0] baabba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cacbc ⇒ acbb
2. ccacbc ⇒ cacbb
3. bba ⇒ acbc
4. acacbc ⇒ aacbb
5. acbccacbc ⇒ acbcacbb
6. cacbacbb ⇒ aacbbcbc
7. baabc ⇒ caacbc
8. baabb ⇒ caacbb
9. bcaacbc ⇒ acbcabc
10. bcaacbb ⇒ acbcabb
11. aaacbb ⇒ 1
12. aacbbcacbc ⇒ cbb
13. baaacb ⇒ 1
14. baaacbc ⇒ c
15. aaacbacbc ⇒ ba
16. baaacbacbb ⇒ acbb
17. baaacbaacbb ⇒ aacbb
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] bc, [2/1] ac, [2/2] aa, [2/3] cb, [2/4] ba, [2/5] bb, [2/6] ca
Length 3:[3/0] acb, [3/1] cbc, [3/2] baa, [3/3] aac, [3/4] cbb, [3/5] aaa, [3/6] cac
Length 4:[4/0] acbc, [4/1] aacb, [4/2] acbb, [4/3] baaa, [4/4] aaac, [4/5] cacb, [4/6] bcaa
Length 5:[5/0] aaacb, [5/1] baaac, [5/2] aacbb, [5/3] cacbc, [5/4] bcaac, [5/5] aacbc, [5/6] bacbb

Considering [length 5 / frequency 0] aaacb=d.

Step 3

Rewriting system is complete. See a, b | aabaabbabba=1⟩.