Morphocompletion for #3044 ⟨a, b | aabaabbabaa=1⟩

Solved by morph:4/0,5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aaaabaabbab ⇒ 1
2. baabbaba ⇒ abaabbab
3. aabaabbabbbaba ⇒ baabbaabaabbab
4. aabaabbabbaabbaabaabbab ⇒ baabbabbbaba
5. aabaabbabbaabbaaabaabbab ⇒ baabbabbbabaa
6. aabaabbabbaabbabbbaba ⇒ baabbabbaabbaabaabbab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aab, [3/1] bba, [3/2] abb, [3/3] bab
Length 4:[4/0] bbab, [4/1] abba, [4/2] baab, [4/3] aabb
Length 5:[5/0] abbab, [5/1] baabb, [5/2] aabba, [5/3] aabaa
Length 6:[6/0] baabba, [6/1] aabbab, [6/2] aabaab, [6/3] abaabb

Considering [length 4 / frequency 0] bbab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. caaaaba ⇒ acaaaab
2. aabaac ⇒ caaaab
3. aaaabaac ⇒ 1
4. baaca ⇒ abaac
5. caacaaa ⇒ bb
6. aabaabb ⇒ caaa
7. bbab ⇒ c
8. caaacaaaab ⇒ ca
9. bbac ⇒ cbab
10. aacaaaabc ⇒ c
11. aabaaccaaa ⇒ baabb
12. aacaaaabbb ⇒ bb
13. bbaabaac ⇒ caaca
14. bbaaabaac ⇒ caacaa
15. aacaaaabbc ⇒ bc
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ac, [2/2] ab, [2/3] bb, [2/4] ca, [2/5] ba, [2/6] bc
Length 3:[3/0] aaa, [3/1] aac, [3/2] aab, [3/3] caa, [3/4] baa, [3/5] bba, [3/6] aba
Length 4:[4/0] caaa, [4/1] baac, [4/2] aaba, [4/3] aaca, [4/4] aaab, [4/5] aaaa, [4/6] abaa
Length 5:[5/0] abaac, [5/1] aabaa, [5/2] aacaa, [5/3] aaaab, [5/4] caaaa, [5/5] acaaa, [5/6] aaaba

Considering [length 5 / frequency 0] abaac=d.

Step 3

Rewriting system is complete. See a, b | aabaabbabaa=1⟩.