Morphocompletion for #3042 ⟨a, b | aabaabbaaba=1⟩

Solved by morph:4/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabaab ⇒ baabaaa
2. baaabaab ⇒ bbaabaaa
3. abaabb ⇒ bbaaba
4. aabbaaba ⇒ baabaaab
5. bbaabaaabaa ⇒ 1
6. baabbaaba ⇒ bbaabaaab
7. abbaabaaab ⇒ bbaabaaaba
8. aaababbaaba ⇒ baabaaaaabb
9. bbaabaaaaaabaab ⇒ baaa
10. bbaababaabaaabaa ⇒ abaab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aab, [3/1] baa, [3/2] aba, [3/3] aaa
Length 4:[4/0] baab, [4/1] aaba, [4/2] abaa, [4/3] bbaa
Length 5:[5/0] baaba, [5/1] aabaa, [5/2] bbaab, [5/3] abaab
Length 6:[6/0] bbaaba, [6/1] aaabaa, [6/2] aabaab, [6/3] abbaab

Considering [length 4 / frequency 0] baab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. acc ⇒ cca
2. aaac ⇒ caaa
3. ccaaa ⇒ 1
4. ccacaaa ⇒ ac
5. ccaacaaa ⇒ aac
6. ccacacaaa ⇒ acac
7. ccacaacaaa ⇒ acaac
8. ccaacacaaa ⇒ aacac
9. ccacacacaaa ⇒ acacac
10. ccaacaacaaa ⇒ aacaac
11. acb ⇒ bca
12. caab ⇒ baac
13. caaab ⇒ aabca
14. caaaaab ⇒ aaabaac
15. caaaaaab ⇒ aaaaabca
16. baab ⇒ c
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ca, [2/2] ac, [2/3] cc, [2/4] ab, [2/5] cb, [2/6] ba
Length 3:[3/0] aaa, [3/1] caa, [3/2] cca, [3/3] aca, [3/4] aab, [3/5] cac, [3/6] aac
Length 4:[4/0] caaa, [4/1] acaa, [4/2] caca, [4/3] ccaa, [4/4] ccac, [4/5] aaab, [4/6] aaaa
Length 5:[5/0] acaaa, [5/1] ccaca, [5/2] ccaac, [5/3] caaca, [5/4] cacaa, [5/5] aaaab, [5/6] aacaa

Considering [length 3 / frequency 0] aaa=d.

Step 3

Rewriting system is complete. See a, b | aabaabbaaba=1⟩.