Morphocompletion for #3020 ⟨a, b | aabaaababaa=1⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#	Rule
1.	aaaabaaabab ⇒ 1
2.	baaababa ⇒ abaaabab
3.	aaabaaababbaba ⇒ baaabaabaaabab
4.	aaabaaababbaabaaabab ⇒ baaabbaba
5.	aaabaaababbaaabaaabab ⇒ baaabbabaa
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:	[3/0] aba, [3/1] aaa, [3/2] aab, [3/3] bab, [3/4] baa, [3/5] bba, [3/6] abb
Length 4:	[4/0] aaab, [4/1] aaba, [4/2] abab, [4/3] baaa, [4/4] abaa, [4/5] baba, [4/6] babb
Length 5:	[5/0] aaaba, [5/1] aabab, [5/2] baaab, [5/3] abaaa, [5/4] aabaa, [5/5] babba, [5/6] ababb
Length 6:	[6/0] aaabab, [6/1] baaaba, [6/2] aaabaa, [6/3] abaaab, [6/4] aabaaa, [6/5] ababba, [6/6] aababb
Length 7:	[7/0] baaabab, [7/1] aaabaaa, [7/2] abaaaba, [7/3] aabaaab, [7/4] aababba, [7/5] aaababb, [7/6] babbaba

Considering [length 3 / frequency 0] aba=c.

Reduction order:
- Right-to-left recursive path with deg(a) = deg(c) = 0, a < c; deg(b) = 1
Auxiliary generators:
1. aba=c

Rewriting system is complete. See ⟨a, b | aabaaababaa=1⟩.