Morphocompletion for #3012 ⟨a, b | aabaaaababa=1⟩

Back:⟨a, b | aabaaaababa=1⟩

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababaa ⇒ baaaab
2. aabaaaab ⇒ baaabaaa
3. aaabab ⇒ baaaba
4. aaaabab ⇒ abaaaba
5. babaaabaaaa ⇒ 1
6. aaabbaaaab ⇒ baaabaabaa
7. ababbaaaba ⇒ babaaabaab
8. babaaabaabaaaba ⇒ abab
9. babaaabaaabaaaba ⇒ aabab
10. babaaabaabbaaaba ⇒ ababb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aba, [3/1] aaa, [3/2] aab, [3/3] baa, [3/4] bab, [3/5] abb, [3/6] bba
Length 4:[4/0] aaab, [4/1] aaba, [4/2] abaa, [4/3] baaa, [4/4] baba, [4/5] abab, [4/6] aaaa
Length 5:[5/0] aaaba, [5/1] babaa, [5/2] baaab, [5/3] abaaa, [5/4] aabaa, [5/5] aaaab, [5/6] aabab
Length 6:[6/0] baaaba, [6/1] babaaa, [6/2] abaaab, [6/3] aabaaa, [6/4] aaabaa, [6/5] baaaab, [6/6] abbaaa
Length 7:[7/0] abaaaba, [7/1] babaaab, [7/2] baaabaa, [7/3] bbaaaba, [7/4] aabaaaa, [7/5] aabaaab, [7/6] aaabaaa

Considering [length 7 / frequency 0] abaaaba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabaaaababa=1⟩.