Morphocompletion for #2973 ⟨a, b | aaabbabbaaa=1⟩

Solved by morph:5/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaaabb ⇒ bbaaaaa
2. bbabbaaaaaa ⇒ 1
3. abbabb ⇒ bbabba
4. bbabbaabbaaaaa ⇒ abb
5. bbabbaaabbaaaaa ⇒ aabb
6. bbabbaaaabbaaaaa ⇒ aaabb
7. bbabbaaaaabbaaaaa ⇒ aaaabb
8. abbbbabba ⇒ bbabbaabb
9. bbabbababbaaaaaa ⇒ abbab
10. bbabbaabbbbaaaaa ⇒ abbbb
11. abbbbbbabba ⇒ bbabbaabbbb
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] bb, [2/2] ba, [2/3] ab
Length 3:[3/0] aaa, [3/1] bba, [3/2] abb, [3/3] bab
Length 4:[4/0] aaaa, [4/1] bbab, [4/2] abba, [4/3] babb
Length 5:[5/0] aaaaa, [5/1] bbabb, [5/2] babba, [5/3] abbaa
Length 6:[6/0] bbabba, [6/1] baaaaa, [6/2] abbaaa, [6/3] bbaaaa

Considering [length 5 / frequency 0] aaaaa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ac ⇒ ca
2. aaaaa ⇒ c
3. cbb ⇒ bbc
4. cbbc ⇒ bbcc
5. cabb ⇒ abbc
6. caabb ⇒ aabbc
7. caaabb ⇒ aaabbc
8. bbabbcc ⇒ aaaa
9. bbabbca ⇒ 1
10. cbbabb ⇒ bbabbc
11. cabbabb ⇒ abbabbc
12. bbcbabbca ⇒ cb
13. bbccbabbca ⇒ ccb
14. bbabbabbc ⇒ bb
15. bbabbaabbc ⇒ abb
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] bb, [2/1] ab, [2/2] ca, [2/3] bc, [2/4] ba, [2/5] aa, [2/6] cb
Length 3:[3/0] abb, [3/1] bbc, [3/2] bba, [3/3] bab, [3/4] bca, [3/5] aaa, [3/6] cbb
Length 4:[4/0] babb, [4/1] bbab, [4/2] abbc, [4/3] bbca, [4/4] aabb, [4/5] bbcc, [4/6] aaaa
Length 5:[5/0] bbabb, [5/1] babbc, [5/2] abbca, [5/3] abbab, [5/4] cbabb, [5/5] cbbab, [5/6] babba

Considering [length 3 / frequency 0] abb=d.

Step 3

Rewriting system is complete. See a, b | aaabbabbaaa=1⟩.