Morphocompletion for #2968 ⟨a, b | aaabbabaaba=1⟩

Back:⟨a, b | aaabbabaaba=1⟩

Solved by morph:5/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aabbaba ⇒ baaaabb
2. babaabaa ⇒ aaaabbab
3. aabbabaab ⇒ baaaabbab
4. aaaabbabaab ⇒ 1
5. baaaabbaba ⇒ abaaaabbab
6. bbabaaba ⇒ abbabaab
7. aabaaaabbabb ⇒ b
8. baabaabaaaabb ⇒ ba
9. baabaaaabbab ⇒ b
10. baaabaaaabbab ⇒ ba
11. aaaabbabaaabbabaab ⇒ babaaba
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aab, [3/1] baa, [3/2] aba, [3/3] aaa
Length 4:[4/0] bbab, [4/1] baab, [4/2] aabb, [4/3] abaa
Length 5:[5/0] abbab, [5/1] aabba, [5/2] bbaba, [5/3] abaab
Length 6:[6/0] aabbab, [6/1] aaaabb, [6/2] babaab, [6/3] abbaba

Considering [length 5 / frequency 0] abbab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaacaab ⇒ 1
2. caaba ⇒ acaab
3. baaac ⇒ acaab
4. aaacac ⇒ bab
5. caaacaa ⇒ abba
6. abbab ⇒ c
7. baaaabba ⇒ acaa
8. babaabaa ⇒ aaac
9. aaacaacaab ⇒ babaaba
10. abbc ⇒ cbab
11. abbaaaac ⇒ cabaabaa
12. aacaabc ⇒ bbab
13. bbabaaba ⇒ caab
14. cabaabaaaab ⇒ abba
15. abbacaab ⇒ cbabaaba
16. acaabbbab ⇒ caabc
17. bbabaabc ⇒ caabbbab
18. acaabbbc ⇒ caabcbab
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] ac, [2/4] ca, [2/5] bb, [2/6] bc
Length 3:[3/0] aab, [3/1] aaa, [3/2] caa, [3/3] baa, [3/4] abb, [3/5] aca, [3/6] aac
Length 4:[4/0] caab, [4/1] acaa, [4/2] aaac, [4/3] bbab, [4/4] abba, [4/5] aaca, [4/6] abaa
Length 5:[5/0] acaab, [5/1] aacaa, [5/2] aaaca, [5/3] bbaba, [5/4] babaa, [5/5] baaba, [5/6] abaab

Considering [length 4 / frequency 0] caab=d.

Step 3

Rewriting system is complete. See ⟨a, b | aaabbabaaba=1⟩.