Morphocompletion for #2964 ⟨a, b | aaabbaabbaa=1⟩

Solved by morph:3/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. bbaaa ⇒ aaabb
2. bbaabba ⇒ abbaabb
3. aaaaabbaabb ⇒ 1
4. bbaaabbaabb ⇒ aabbaabbbba
5. bbaaaabbaabb ⇒ aabbaabbbbaa
6. aabbaabbbbaaa ⇒ bb
7. aaaaaabbbbaabb ⇒ bba
8. aaaaaabbabbaabb ⇒ bbaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] bb, [2/2] ba, [2/3] ab
Length 3:[3/0] aaa, [3/1] abb, [3/2] bba, [3/3] aab
Length 4:[4/0] aabb, [4/1] bbaa, [4/2] aaaa, [4/3] abba
Length 5:[5/0] baabb, [5/1] bbaab, [5/2] aabba, [5/3] aaaaa
Length 6:[6/0] bbaabb, [6/1] abbaab, [6/2] aabbaa, [6/3] aaabba

Considering [length 3 / frequency 0] aaa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ca ⇒ ac
2. cbb ⇒ bbc
3. aaa ⇒ c
4. bbaaccba ⇒ abaabbcc
5. bbaabbcc ⇒ a
6. bbcbaabbcc ⇒ cba
7. bbccbaabbcc ⇒ ccba
8. bbaabbaac ⇒ 1
9. bbaabbbbcc ⇒ abb
10. bbcbaabbacc ⇒ cbaa
11. bbaabbabbcc ⇒ aabb
12. bbaabbbbacc ⇒ abba
13. bbcbaabbaac ⇒ cb
14. bbccbaabbaac ⇒ ccb
15. bbaabbaabbc ⇒ bb
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] bb, [2/1] ba, [2/2] aa, [2/3] cc, [2/4] ab, [2/5] bc, [2/6] ac
Length 3:[3/0] bba, [3/1] bbc, [3/2] baa, [3/3] abb, [3/4] aab, [3/5] bcc, [3/6] cba
Length 4:[4/0] bbaa, [4/1] bbcc, [4/2] baab, [4/3] aabb, [4/4] baac, [4/5] abba, [4/6] bbcb
Length 5:[5/0] bbaab, [5/1] baabb, [5/2] bbaac, [5/3] abbcc, [5/4] aabba, [5/5] bbcba, [5/6] cbaab

Considering [length 4 / frequency 0] bbaa=d.

Step 3

Rewriting system is complete. See a, b | aaabbaabbaa=1⟩.