Morphocompletion for #2930 ⟨a, b | aaababaabaa=1⟩

Solved by morph:6/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaaaab ⇒ baabaaaa
2. aaaabab ⇒ baabaaa
3. babaabaaaaa ⇒ 1
4. baabaaaaab ⇒ babaabaaaa
5. ababaab ⇒ babaaba
6. aababaab ⇒ babaabaa
7. ababaaababa ⇒ ababbaaaaab
8. babaabaabaabaaa ⇒ abab
9. babaabaaabaabaaa ⇒ aabab
10. ababbabaabaa ⇒ babaabaabaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aba, [3/1] aab, [3/2] baa, [3/3] aaa, [3/4] bab, [3/5] abb, [3/6] bba
Length 4:[4/0] abaa, [4/1] baab, [4/2] aaba, [4/3] baba, [4/4] abab, [4/5] baaa, [4/6] aaaa
Length 5:[5/0] abaab, [5/1] babaa, [5/2] aabaa, [5/3] abaaa, [5/4] baaba, [5/5] ababa, [5/6] aaaab
Length 6:[6/0] babaab, [6/1] baabaa, [6/2] abaaba, [6/3] aabaaa, [6/4] ababaa, [6/5] aababa, [6/6] aaaaab
Length 7:[7/0] abaabaa, [7/1] baabaaa, [7/2] babaaba, [7/3] abaaaaa, [7/4] baaaaab, [7/5] aabaaba, [7/6] ababbab

Considering [length 6 / frequency 0] babaab=c.

Step 2

Rewriting system is complete. See a, b | aaababaabaa=1⟩.