Morphocompletion for #2928 ⟨a, b | aaababaaaba=1⟩

Back:⟨a, b | aaababaaaba=1⟩

Solved by morph:7/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababaa ⇒ baaaab
2. ababaaa ⇒ baaaaba
3. aabaaaab ⇒ baaabaaa
4. aabaaaaba ⇒ baaabaaaa
5. aaabab ⇒ baaaba
6. babaaabaaaa ⇒ 1
7. baaabaaaab ⇒ babaaabaaa
8. aaabbaaaab ⇒ baaabaabaa
9. baaabaabaaabaaa ⇒ aaab
10. baaaabaababaa ⇒ ab
11. ababbaaaba ⇒ babaaabaab
12. babaaabaabaaaba ⇒ abab
13. babaaabaaabaaaba ⇒ aabab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aba, [3/1] aaa, [3/2] baa, [3/3] aab, [3/4] bab, [3/5] abb, [3/6] bba
Length 4:[4/0] aaba, [4/1] baaa, [4/2] aaab, [4/3] abaa, [4/4] abab, [4/5] baba, [4/6] aaaa
Length 5:[5/0] aaaba, [5/1] abaaa, [5/2] aabaa, [5/3] baaab, [5/4] babaa, [5/5] aaaab, [5/6] baaaa
Length 6:[6/0] baaaba, [6/1] aabaaa, [6/2] baaaab, [6/3] babaaa, [6/4] aaabaa, [6/5] abaaab, [6/6] abaaaa
Length 7:[7/0] abaaaba, [7/1] baaabaa, [7/2] aabaaaa, [7/3] babaaab, [7/4] aaabaaa, [7/5] abaaaab, [7/6] aabaaab

Considering [length 7 / frequency 1] baaabaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaababaaaba=1⟩.