Morphocompletion for #2927 ⟨a, b | aaababaaaab=1⟩

Back:⟨a, b | aaababaaaab=1⟩

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aababa ⇒ baaaab
2. baaaabaa ⇒ aaabaaab
3. ababaaa ⇒ aabaaab
4. aaaabaaabab ⇒ 1
5. babaaaab ⇒ abaaabab
6. baaaabbaaa ⇒ aabaabaaab
7. aabaaababba ⇒ babaabaaaab
8. aabaaabaabaaabab ⇒ ababa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aaa, [3/1] aba, [3/2] aab, [3/3] baa, [3/4] bab, [3/5] bba, [3/6] abb
Length 4:[4/0] baaa, [4/1] aaba, [4/2] abaa, [4/3] aaab, [4/4] abab, [4/5] baba, [4/6] aaaa
Length 5:[5/0] aabaa, [5/1] aabab, [5/2] abaaa, [5/3] aaaba, [5/4] aaaab, [5/5] baaaa, [5/6] ababa
Length 6:[6/0] baaaab, [6/1] aabaaa, [6/2] aaabab, [6/3] babaaa, [6/4] baaaba, [6/5] abaaab, [6/6] aaabaa
Length 7:[7/0] aabaaab, [7/1] baaabab, [7/2] abaaaba, [7/3] aaaabaa, [7/4] aababba, [7/5] baaaabb, [7/6] babaaaa

Considering [length 7 / frequency 0] aabaaab=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaababaaaab=1⟩.