Morphocompletion for #2922 ⟨a, b | aaabaabbaba=1⟩

Solved by morph:5/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. bbabaaa ⇒ aabaabb
2. aaaabaabbab ⇒ 1
3. baabbaba ⇒ abaabbab
4. aabaabbaabaabbab ⇒ bbaba
5. aabaabbaaabaabbab ⇒ bbabaa
6. aabaabbabbbaba ⇒ baabbaabaabbab
7. aabaabbabbaabbabbbaba ⇒ baabbabbaabbaabaabbab
8. aabaabbabbaabbabbaabbabbbaba ⇒ baabbabbaabbabbaabbaabaabbab
9. aabaabbabbaabbabbaabbabbaabbabbbaba ⇒ baabbabbaabbabbaabbabbaabbaabaabbab
10. aabaabbabbaabbabbaabbabbaabbabbaabbabbbaba ⇒ baabbabbaabbabbaabbabbaabbabbaabbaabaabbab
11. aabaabbabbaabbabbaabbabbaabbabbaabbabbaabbabbbaba ⇒ baabbabbaabbabbaabbabbaabbabbaabbabbaabbaabaabbab
12. aabaabbabbaabbabbaabbabbaabbabbaabbabbaabbabbaabbabbbaba ⇒ baabbabbaabbabbaabbabbaabbabbaabbabbaabbabbaabbaabaabbab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ba, [2/1] ab, [2/2] bb, [2/3] aa
Length 3:[3/0] bba, [3/1] abb, [3/2] aab, [3/3] bab
Length 4:[4/0] abba, [4/1] bbab, [4/2] baab, [4/3] aabb
Length 5:[5/0] abbab, [5/1] baabb, [5/2] aabba, [5/3] bbabb
Length 6:[6/0] baabba, [6/1] aabbab, [6/2] abbabb, [6/3] abbaab

Considering [length 5 / frequency 0] abbab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. caaaaba ⇒ 1
2. aaabac ⇒ caaaab
3. aaaabac ⇒ 1
4. baca ⇒ abac
5. acaaac ⇒ bab
6. cacaaa ⇒ abb
7. aaabaabb ⇒ caaa
8. abbab ⇒ c
9. babaaaaba ⇒ acaaa
10. abbc ⇒ cbab
11. caaaabc ⇒ bbab
12. aaabacc ⇒ bbab
13. abaccaaa ⇒ baabb
14. cbabaaaaba ⇒ abb
15. abbaabac ⇒ caca
16. abbaaabac ⇒ cacaa
17. abbbbab ⇒ cacaac
18. abacbbab ⇒ bacc
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] ac, [2/4] ca, [2/5] bb, [2/6] bc
Length 3:[3/0] aaa, [3/1] aba, [3/2] bac, [3/3] abb, [3/4] aab, [3/5] bab, [3/6] caa
Length 4:[4/0] abac, [4/1] aaba, [4/2] aaab, [4/3] caaa, [4/4] bbab, [4/5] abba, [4/6] aaaa
Length 5:[5/0] aaaba, [5/1] aabac, [5/2] aaaab, [5/3] abacc, [5/4] abbaa, [5/5] caaaa, [5/6] acaaa

Considering [length 4 / frequency 0] abac=d.

Step 3

Rewriting system is complete. See a, b | aaabaabbaba=1⟩.