Morphocompletion for #2922 ⟨a, b | aaabaabbaba=1⟩

Solved by morph:5/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. bbabaaa ⇒ aabaabb
2. aaaabaabbab ⇒ 1
3. baabbaba ⇒ abaabbab
4. aabaabbaabaabbab ⇒ bbaba
5. aabaabbaaabaabbab ⇒ bbabaa
6. aabaabbabbbaba ⇒ baabbaabaabbab
7. aabaabbabbaabbabbbaba ⇒ baabbabbaabbaabaabbab
8. aabaabbabbaabbabbaabbabbbaba ⇒ baabbabbaabbabbaabbaabaabbab
9. aabaabbabbaabbabbaabbabbaabbabbbaba ⇒ baabbabbaabbabbaabbabbaabbaabaabbab
10. aabaabbabbaabbabbaabbabbaabbabbaabbabbbaba ⇒ baabbabbaabbabbaabbabbaabbabbaabbaabaabbab
11. aabaabbabbaabbabbaabbabbaabbabbaabbabbaabbabbbaba ⇒ baabbabbaabbabbaabbabbaabbabbaabbabbaabbaabaabbab
12. aabaabbabbaabbabbaabbabbaabbabbaabbabbaabbabbaabbabbbaba ⇒ baabbabbaabbabbaabbabbaabbabbaabbabbaabbabbaabbaabaabbab
...

Collecting factors up to length 7 / frequency 4:

[2/0]ba94lf:85,lp:1,ls:8,rf:77,rp:7,rs:1,lsrp:7,a:3
[2/1]ab89lf:86,ls:3,rf:77,rp:1,rs:8,a:3
[2/2]bb71lf:70,lp:1,rf:60,rp:2,rs:1,lprs:1,a:3
[2/3]aa62lf:51,lp:10,ls:1,rf:46,rp:1,rs:1,lsrp:1,lprs:1,a:3
[3/0]bba64lf:63,lp:1,rf:59,rp:2,a:3
[3/1]abb62lf:62,rf:58,rs:1,a:3
[3/2]aab55lf:46,lp:9,rf:45,rp:1,a:3
[3/3]bab43lf:40,ls:3,rf:31,rs:8,a:3
[4/0]abba55lf:55,rf:57,a:3
[4/1]bbab44lf:40,lp:1,ls:3,rf:31,rp:2,rs:8,lsrp:2,a:3
[4/2]baab36lf:35,lp:1,rf:44,rp:7,a:3
[4/3]aabb34lf:34,rf:37,rs:1,a:3
[5/0]abbab35lf:32,ls:3,rf:29,rs:8,a:3
[5/1]baabb35lf:34,lp:1,rf:37,rp:7,rs:1,a:3
[5/2]aabba34lf:34,rf:36,a:3
[5/3]bbabb28lf:28,rf:21,a:4
[6/0]baabba35lf:34,lp:1,rf:36,rp:7,a:3
[6/1]aabbab35lf:32,ls:3,rf:29,rs:8,a:3
[6/2]abbabb28lf:28,rf:21,a:4
[6/3]abbaab22lf:22,rf:28,a:4

Considering [length 5 / frequency 0] abbab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. caaaaba ⇒ 1
2. aaabac ⇒ caaaab
3. aaaabac ⇒ 1
4. baca ⇒ abac
5. acaaac ⇒ bab
6. cacaaa ⇒ abb
7. aaabaabb ⇒ caaa
8. abbab ⇒ c
9. babaaaaba ⇒ acaaa
10. abbc ⇒ cbab
11. caaaabc ⇒ bbab
12. aaabacc ⇒ bbab
13. abaccaaa ⇒ baabb
14. cbabaaaaba ⇒ abb
15. abbaabac ⇒ caca
16. abbaaabac ⇒ cacaa
17. abbbbab ⇒ cacaac
18. abacbbab ⇒ bacc
...

Collecting factors up to length 6 / frequency 7:

[2/0]aa37lf:31,lp:4,ls:2,rf:10,rs:3,lprs:1,a:4
[2/1]ab33lf:23,lp:7,ls:3,rf:9,rp:3,rs:5,lprs:1,a:1
[2/2]ba26lf:21,lp:2,ls:3,rf:7,rp:3,a:1
[2/3]ac17lf:11,lp:1,ls:5,rf:7,rp:1,rs:2,a:4
[2/4]ca11lf:7,lp:3,ls:1,rf:9,rp:5,rs:1,a:10
[2/5]bb10lf:9,ls:1,rf:5,rp:2,rs:3,a:1
[2/6]bc4lf:2,ls:2,a:3
[3/0]aaa23lf:17,lp:4,ls:2,rf:4,rs:2,lprs:1,a:4
[3/1]aba18lf:13,lp:2,ls:3,rf:1,rp:1,a:4
[3/2]bac13lf:8,lp:1,ls:4,rf:2,rp:1,rs:1,lprs:10,a:4
[3/3]abb12lf:6,lp:5,ls:1,rf:3,rp:2,rs:3,re:2,a:1
[3/4]aab11lf:11,rf:2,rs:1,a:4
[3/5]bab9lf:5,lp:1,ls:3,rf:4,rp:1,rs:4,re:1,a:1
[3/6]caa7lf:5,lp:2,rf:5,rp:2,rs:1,a:16
[4/0]abac13lf:7,lp:2,ls:4,rf:1,rp:1,rs:1,re:1,a:4
[4/1]aaba12lf:9,ls:3,a:4
[4/2]aaab12lf:9,lp:3,rf:1,rs:1,lprs:1,a:4
[4/3]caaa9lf:5,lp:2,ls:2,rf:3,rp:2,rs:2,re:1,a:21
[4/4]bbab6lf:3,ls:3,rf:2,rp:2,rs:2,re:2,a:1
[4/5]abba6lf:3,lp:3,a:1
[4/6]aaaa6lf:5,lp:1,rf:1,a:29
[5/0]aaaba14lf:8,lp:3,ls:3,a:4
[5/1]aabac9lf:5,ls:4,a:4
[5/2]aaaab6lf:5,lp:1,rf:1,rs:1,a:29
[5/3]abacc4lf:2,lp:1,ls:1,a:4
[5/4]abbaa4lf:2,lp:2,a:11
[5/5]caaaa4lf:2,lp:2,rf:1,rp:1,a:37
[5/6]acaaa4lf:2,lp:1,ls:1,rf:1,rp:1,rs:1,re:1,a:21

Considering [length 4 / frequency 0] abac=d.

Step 3

Rewriting system is complete. See ⟨a, b | aaabaabbaba=1⟩.