Morphocompletion for #2908 ⟨a, b | aaabaaababa=1⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. baaababa ⇒ abaaabab
2. aabaaababa ⇒ aaabaaabab
3. aaabaaababa ⇒ 1
4. baaabbabaaa ⇒ aaabaaababb
5. aaabaaababbaba ⇒ baaabaabaaabab
6. baaabbbabaaa ⇒ aaabaaababbb
7. baaabbbbabaaa ⇒ aaabaaababbbb
8. aaabaaababbaabaaabab ⇒ baaabbaba
9. aaabaaababbaaabaaabab ⇒ baaabbabaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aba, [3/1] aaa, [3/2] baa, [3/3] aab, [3/4] bab, [3/5] bba, [3/6] abb
Length 4:[4/0] baaa, [4/1] aaab, [4/2] aaba, [4/3] baba, [4/4] abab, [4/5] abaa, [4/6] bbab
Length 5:[5/0] aaaba, [5/1] baaab, [5/2] abaaa, [5/3] aabab, [5/4] aabaa, [5/5] ababa, [5/6] bbaba
Length 6:[6/0] baaaba, [6/1] aaabab, [6/2] aaabaa, [6/3] aabaaa, [6/4] abaaab, [6/5] baaabb, [6/6] babaaa
Length 7:[7/0] baaabab, [7/1] aaabaaa, [7/2] aabaaab, [7/3] abaaaba, [7/4] bbabaaa, [7/5] aaababa, [7/6] baaabbb

Considering [length 3 / frequency 0] aba=c.

Step 2

Rewriting system is complete. See a, b | aaabaaababa=1⟩.