Morphocompletion for #2875 ⟨a, b | aaaabbaabba=1⟩

Solved by morph:3/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaabb ⇒ bbaaa
2. abaabbaaaaa ⇒ bbaaaaaaaab
3. aabbaaaaab ⇒ baabbaaaaa
4. bbaabbaaaaa ⇒ 1
5. abbaabb ⇒ bbaabba
6. bbaaabaabbaaaaa ⇒ aaab
7. bbaabbbbaaaaaa ⇒ abb
8. bbaabbabbaaaaaa ⇒ aabb
9. abbbbaabb ⇒ bbaabbbba
10. bbaabbbbbbaaaaaa ⇒ abbbb
11. bbaabbbbabbaaaaaa ⇒ abbabb
12. bbaabbabbbbaaaaaa ⇒ aabbbb
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] bb, [2/2] ab, [2/3] ba
Length 3:[3/0] aaa, [3/1] bba, [3/2] abb, [3/3] baa
Length 4:[4/0] aaaa, [4/1] bbaa, [4/2] aabb, [4/3] abba
Length 5:[5/0] aaaaa, [5/1] bbaab, [5/2] baabb, [5/3] bbaaa
Length 6:[6/0] bbaabb, [6/1] baaaaa, [6/2] aaaaaa, [6/3] bbaaaa

Considering [length 3 / frequency 0] aaa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ac ⇒ ca
2. aaa ⇒ c
3. cbb ⇒ bbc
4. cabb ⇒ abbc
5. caabb ⇒ aabbc
6. bbaabbcc ⇒ a
7. bbaabbcaa ⇒ 1
8. cbbaabb ⇒ bbaabbc
9. abbaabb ⇒ bbaabba
10. abbaabbc ⇒ bbaabbca
11. bbcbaabbcc ⇒ cba
12. bbcbaabbcaa ⇒ cb
13. bbccbaabbcc ⇒ ccba
14. bbaabbbbcc ⇒ abb
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] bb, [2/1] aa, [2/2] ab, [2/3] bc, [2/4] ba, [2/5] cc, [2/6] cb
Length 3:[3/0] abb, [3/1] bbc, [3/2] aab, [3/3] bba, [3/4] baa, [3/5] bcc, [3/6] caa
Length 4:[4/0] aabb, [4/1] bbcc, [4/2] baab, [4/3] bbaa, [4/4] abbc, [4/5] bbcb, [4/6] abba
Length 5:[5/0] baabb, [5/1] bbaab, [5/2] aabbc, [5/3] abbcc, [5/4] bbcba, [5/5] abbaa, [5/6] bbcaa

Considering [length 4 / frequency 0] aabb=d.

Step 3

Rewriting system is complete. See a, b | aaaabbaabba=1⟩.