Morphocompletion for #2831 ⟨a, b | aaaaabbabba=1⟩

Solved by morph:3/0,5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. bbabbaaaaaa ⇒ 1
2. abbabb ⇒ bbabba
3. bbabbaabbaaaaa ⇒ abb
4. bbabbaaabbaaaaa ⇒ aabb
5. bbabbaaaabbaaaaa ⇒ aaabb
6. abbbbabba ⇒ bbabbaabb
7. bbabbababbaaaaaa ⇒ abbab
8. bbabbaabbbbaaaaa ⇒ abbbb
9. abbbbbbabba ⇒ bbabbaabbbb
10. abbbbbbbbabba ⇒ bbabbaabbbbbb
11. abbbbbbbbbbabba ⇒ bbabbaabbbbbbbb
12. abbbbbbbbbbbbabba ⇒ bbabbaabbbbbbbbbb
...

Collecting factors up to length 7 / frequency 4:

[2/0]bb68lf:61,lp:6,ls:1,rf:44,rp:6,rs:9,lsrp:1,lprs:4,a:6
[2/1]aa39lf:33,ls:6,rf:8,rp:2,lsrp:2,a:8
[2/2]ba34lf:29,ls:5,rf:13,rs:1,a:6
[2/3]ab30lf:24,lp:6,rf:17,rp:3,rs:1,a:6
[3/0]bba39lf:28,lp:6,ls:5,rf:13,rp:6,rs:1,lsrp:5,a:6
[3/1]bbb32lf:32,rf:22,rs:5,a:8
[3/2]abb30lf:23,lp:6,ls:1,rf:16,rp:3,rs:4,re:1,lprs:1,a:6
[3/3]aaa29lf:23,ls:6,rf:1,rp:1,lsrp:1,a:14
[4/0]bbbb26lf:26,rf:17,rs:5,a:8
[4/1]abba22lf:16,lp:1,ls:5,rf:7,rp:1,rs:1,lprs:1,a:6
[4/2]aaaa21lf:15,ls:6,a:14
[4/3]bbab19lf:13,lp:6,rf:7,rp:6,rs:1,lprs:1,a:6
[5/0]bbbbb20lf:20,rf:12,rs:3,a:9
[5/1]bbabb19lf:12,lp:6,ls:1,rf:6,rp:6,lsrp:10,a:6
[5/2]babba17lf:12,ls:5,rf:6,rs:1,a:6
[5/3]aaaaa14lf:8,ls:6,a:14
[6/0]bbabba22lf:11,lp:6,ls:5,rf:6,rp:6,rs:1,re:1,lsrp:5,a:6
[6/1]bbbbbb16lf:16,rf:9,rs:3,a:9
[6/2]baaaaa10lf:6,ls:4,a:14
[6/3]abbbbb8lf:4,lp:4,rf:3,a:9

Considering [length 3 / frequency 0] bba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. acc ⇒ cca
2. ccaaaaa ⇒ 1
3. ccacaaaaa ⇒ ac
4. ccaacaaaaa ⇒ aac
5. ccacacaaaaa ⇒ acac
6. ccaaacaaaaa ⇒ aaac
7. ccbacaaaaac ⇒ ccba
8. acb ⇒ ccbacaaaaa
9. acbc ⇒ ccba
10. acbcccaaaa ⇒ ccb
11. cccaaaab ⇒ bcccaaaa
12. bb ⇒ cccaaaa
13. ccbacaaaaab ⇒ cc
...

Collecting factors up to length 6 / frequency 7:

[2/0]aa43lf:37,ls:6,rf:13,rp:2,rs:3,lsrp:2,a:3
[2/1]cc21lf:12,lp:8,ls:1,rf:10,rp:7,rs:1,re:1,lprp:2,lsrp:10,lprs:1,a:3
[2/2]ac17lf:12,lp:4,ls:1,rf:6,rp:2,rs:4,re:1,a:20
[2/3]ca14lf:14,rf:5,rs:1,a:3
[2/4]cb6lf:5,ls:1,rf:4,rs:1,a:32
[2/5]ab4lf:2,ls:2,a:23
[2/6]bc3lf:2,ls:1,rf:1,rp:1,a:23
[3/0]aaa32lf:26,ls:6,rf:8,rp:1,rs:3,lsrp:1,a:3
[3/1]cca12lf:7,lp:5,rf:3,rp:1,rs:1,re:1,a:3
[3/2]caa11lf:11,rf:3,a:3
[3/3]aca7lf:7,rf:2,rp:1,a:21
[3/4]aab4lf:2,ls:2,a:23
[3/5]acb4lf:2,lp:2,a:32
[3/6]ccb4lf:2,lp:2,rf:4,rp:4,rs:1,re:1,lprp:1,a:32
[4/0]aaaa22lf:16,ls:6,rf:4,rs:3,a:3
[4/1]caaa10lf:10,rf:3,a:3
[4/2]ccaa8lf:5,lp:3,rf:2,a:3
[4/3]acaa6lf:6,rf:1,a:21
[4/4]aaab4lf:2,ls:2,a:23
[4/5]ccba4lf:2,lp:2,rf:3,rp:3,rs:2,re:2,lprp:1,lprs:1,a:36
[4/6]ccac4lf:2,lp:2,a:22
[5/0]aaaaa12lf:7,ls:5,rf:1,rs:1,a:19
[5/1]caaaa10lf:9,ls:1,rf:3,rs:2,a:3
[5/2]acaaa6lf:6,rf:1,a:21
[5/3]ccaaa6lf:4,lp:2,rf:2,a:3
[5/4]aaaab4lf:2,ls:2,a:23
[5/5]ccbac4lf:2,lp:2,rf:1,rp:1,a:37
[5/6]ccaca4lf:2,lp:2,a:22

Considering [length 5 / frequency 0] aaaaa=d.

Step 3

Rewriting system is complete. See ⟨a, b | aaaaabbabba=1⟩.