| Back: | ⟨a, b | baabb=aabba⟩ |
|---|
Solved by morph:3/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabba ⇒ baabb |
| 2. | aabbbaabb ⇒ bbaabbbba |
| 3. | aabbbbaabb ⇒ bbaabbbbaa |
| 4. | aabbbbbaabb ⇒ bbaabbbbaaa |
| 5. | aabbbbbbaabb ⇒ bbaabbbbaaaa |
| 6. | aabbbbbbbaabb ⇒ bbaabbbbaaaaa |
| 7. | aabbbbbbbbaabb ⇒ bbaabbbbaaaaaa |
| 8. | aabbbbbbbbbaabb ⇒ bbaabbbbaaaaaaa |
| 9. | aabbbbbbbbbbaabb ⇒ bbaabbbbaaaaaaaa |
| 10. | aabbbbbbbbbbbaabb ⇒ bbaabbbbaaaaaaaaa |
| 11. | aabbbbbbbbbbbbaabb ⇒ bbaabbbbaaaaaaaaaa |
| 12. | aabbbbbbbbbbbbbaabb ⇒ bbaabbbbaaaaaaaaaaa |
| 13. | aabbbbbbbbbbbbbbaabb ⇒ bbaabbbbaaaaaaaaaaaa |
| 14. | aabbbbbbbbbbbbbbbaabb ⇒ bbaabbbbaaaaaaaaaaaaa |
| 15. | aabbbbbbbbbbbbbbbbaabb ⇒ bbaabbbbaaaaaaaaaaaaaa |
| 16. | aabbbbbbbbbbbbbbbbbaabb ⇒ bbaabbbbaaaaaaaaaaaaaaa |
| 17. | aabbbbbbbbbbbbbbbbbbaabb ⇒ bbaabbbbaaaaaaaaaaaaaaaa |
| 18. | aabbbbbbbbbbbbbbbbbbbaabb ⇒ bbaabbbbaaaaaaaaaaaaaaaaa |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | bb | 205 | lf:188,ls:17,rf:69,rp:17,rs:1,lsrp:17 |
|---|---|---|---|
| [2/1] | aa | 53 | lf:35,lp:18,rf:154,rs:16,lprs:16 |
| [2/2] | ab | 35 | lf:35,rf:18 |
| [2/3] | ba | 19 | lf:18,ls:1,rf:35,rp:1,rs:1,lsrp:1 |
| [3/0] | bbb | 153 | lf:153,rf:34,a:1 |
| [3/1] | aab | 53 | lf:35,lp:18,rf:18 |
| [3/2] | abb | 52 | lf:35,ls:17,rf:18,rs:1 |
| [3/3] | bba | 19 | lf:18,ls:1,rf:34,rp:17,rs:1 |
| [3/4] | baa | 17 | lf:17,rf:34,rp:1,rs:1 |
| [3/5] | aaa | 0 | rf:120,rs:15,a:6 |
| [4/0] | bbbb | 136 | lf:136,rf:17,a:1 |
| [4/1] | aabb | 70 | lf:35,lp:18,ls:17,rf:18,rs:1,lprs:10 |
| [4/2] | abbb | 17 | lf:17,rf:17,a:1 |
| [4/3] | baab | 17 | lf:17,rf:18,rp:1 |
| [4/4] | bbaa | 17 | lf:17,rf:33,rp:17,rs:1,a:1 |
| [4/5] | bbba | 17 | lf:17,rf:17,rs:1,a:1 |
| [4/6] | abba | 2 | lf:1,ls:1 |
| [5/0] | bbbbb | 120 | lf:120,a:6 |
| [5/1] | aabbb | 34 | lf:17,lp:17,rf:17,a:1 |
| [5/2] | baabb | 34 | lf:17,ls:17,rf:18,rp:1,rs:1,re:1 |
| [5/3] | bbaab | 17 | lf:17,rf:17,rp:17,a:1 |
| [5/4] | bbbaa | 17 | lf:17,rf:16,rs:1,a:1 |
| [5/5] | abbbb | 16 | lf:16,rf:17,a:1 |
| [5/6] | bbbba | 16 | lf:16,rf:17,rs:1,a:1 |
| [6/0] | bbbbbb | 105 | lf:105,a:9 |
| [6/1] | bbaabb | 34 | lf:17,ls:17,rf:17,rp:17,lsrp:17,a:1 |
| [6/2] | aabbbb | 32 | lf:16,lp:16,rf:17,a:1 |
| [6/3] | bbbaab | 17 | lf:17,a:1 |
| [6/4] | bbbbaa | 16 | lf:16,rf:16,rs:1,a:3 |
| [6/5] | abbbbb | 15 | lf:15,a:6 |
| [6/6] | bbbbba | 15 | lf:15,a:6 |
| [7/0] | bbbbbbb | 91 | lf:91,a:12 |
| [7/1] | bbbaabb | 34 | lf:17,ls:17,a:1 |
| [7/2] | aabbbbb | 30 | lf:15,lp:15,a:6 |
| [7/3] | bbbbaab | 16 | lf:16,a:3 |
| [7/4] | bbbbbaa | 15 | lf:15,a:6 |
| [7/5] | abbbbbb | 14 | lf:14,a:9 |
| [7/6] | bbbbbba | 14 | lf:14,a:9 |
Considering [length 3 / frequency 1] aab=c.
Rewriting system is complete. See ⟨a, b | baabb=aabba⟩.