Morphocompletion for #2750 ⟨a, b | baaba=abaab⟩

Solved by morph:3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. baaba ⇒ abaab
2. baaabaab ⇒ aabaabba
3. baaaabaab ⇒ aabaabbaa
4. baaaaabaab ⇒ aabaabbaaa
5. baaaaaabaab ⇒ aabaabbaaaa
6. baaaaaaabaab ⇒ aabaabbaaaaa
7. baaaaaaaabaab ⇒ aabaabbaaaaaa
8. baaaaaaaaabaab ⇒ aabaabbaaaaaaa
9. baaaaaaaaaabaab ⇒ aabaabbaaaaaaaa
10. baaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaa
11. baaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaa
12. baaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaa
13. baaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaa
14. baaaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaaa
15. baaaaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaaaa
16. baaaaaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaaaaa
17. baaaaaaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaaaaaa
18. baaaaaaaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaaaaaaa
19. baaaaaaaaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaaaaaaaa
20. baaaaaaaaaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaaaaaaaaa
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa229lf:229,rf:210,rp:19,rs:18
[2/1]ba61lf:40,lp:20,ls:1,rf:39,rs:1,lprs:1
[2/2]ab58lf:39,ls:19,rf:40,rp:1,rs:1
[2/3]bb0rf:19,a:1
[3/0]aaa190lf:190,rf:153,rs:17,a:1
[3/1]baa59lf:39,lp:20,rf:38,rs:1,lprs:1
[3/2]aab58lf:39,ls:19,rf:39,rp:19,rs:1,lsrp:19
[3/3]aba21lf:20,ls:1,rf:20,rp:1,lsrp:1
[3/4]bba0rf:19,rs:1,a:1
[3/5]abb0rf:19,a:1
[4/0]aaaa171lf:171,rf:136,rs:16,a:3
[4/1]baab40lf:20,lp:1,ls:19,rf:20,rs:1,lprs:10
[4/2]baaa38lf:19,lp:19,rf:17,rs:1,lprs:1,a:1
[4/3]aaba21lf:20,ls:1,rf:19,rp:19
[4/4]abaa19lf:19,rf:20,rp:1
[4/5]aaab19lf:19,a:1
[4/6]bbaa0rf:18,rs:1,a:3
[5/0]aaaaa153lf:153,rf:120,rs:15,a:4
[5/1]abaab38lf:19,ls:19,rf:20,rp:1,rs:1,re:1
[5/2]baaaa36lf:18,lp:18,rf:16,rs:1,lprs:1,a:3
[5/3]aabaa19lf:19,rf:19,rp:19,a:1
[5/4]aaaba19lf:19,a:1
[5/5]aaaab18lf:18,a:3
[5/6]baaab2lf:1,lp:1,a:1
[6/0]aaaaaa136lf:136,rf:105,rs:14,a:5
[6/1]aabaab38lf:19,ls:19,rf:19,rp:19,lsrp:19,a:1
[6/2]baaaaa34lf:17,lp:17,rf:15,rs:1,lprs:1,a:4
[6/3]aaabaa19lf:19,a:1
[6/4]aaaaba18lf:18,a:3
[6/5]aaaaab17lf:17,a:4
[6/6]baaaba2lf:1,lp:1,a:1
[7/0]aaaaaaa120lf:120,rf:91,rs:13,a:6
[7/1]aaabaab38lf:19,ls:19,a:1
[7/2]baaaaaa32lf:16,lp:16,rf:14,rs:1,lprs:1,a:5
[7/3]aaaabaa18lf:18,a:3
[7/4]aaaaaba17lf:17,a:4
[7/5]aaaaaab16lf:16,a:5
[7/6]baaabaa2lf:1,lp:1,a:1

Considering [length 3 / frequency 1] baa=c.

Step 2

Rewriting system is complete. See ⟨a, b | baaba=abaab⟩.