Morphocompletion for #2750 ⟨a, b | baaba=abaab

Solved by morph:3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. baaba ⇒ abaab
2. baaabaab ⇒ aabaabba
3. baaaabaab ⇒ aabaabbaa
4. baaaaabaab ⇒ aabaabbaaa
5. baaaaaabaab ⇒ aabaabbaaaa
6. baaaaaaabaab ⇒ aabaabbaaaaa
7. baaaaaaaabaab ⇒ aabaabbaaaaaa
8. baaaaaaaaabaab ⇒ aabaabbaaaaaaa
9. baaaaaaaaaabaab ⇒ aabaabbaaaaaaaa
10. baaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaa
11. baaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaa
12. baaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaa
13. baaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaa
14. baaaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaaa
15. baaaaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaaaa
16. baaaaaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaaaaa
17. baaaaaaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaaaaaa
18. baaaaaaaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaaaaaaa
19. baaaaaaaaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaaaaaaaa
20. baaaaaaaaaaaaaaaaaaaaabaab ⇒ aabaabbaaaaaaaaaaaaaaaaaaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aaa, [3/1] baa, [3/2] aab, [3/3] aba, [3/4] bba, [3/5] abb
Length 4:[4/0] aaaa, [4/1] baab, [4/2] baaa, [4/3] aaba, [4/4] abaa, [4/5] aaab, [4/6] bbaa
Length 5:[5/0] aaaaa, [5/1] abaab, [5/2] baaaa, [5/3] aabaa, [5/4] aaaba, [5/5] aaaab, [5/6] baaab
Length 6:[6/0] aaaaaa, [6/1] aabaab, [6/2] baaaaa, [6/3] aaabaa, [6/4] aaaaba, [6/5] aaaaab, [6/6] baaaba
Length 7:[7/0] aaaaaaa, [7/1] aaabaab, [7/2] baaaaaa, [7/3] aaaabaa, [7/4] aaaaaba, [7/5] aaaaaab, [7/6] baaabaa

Considering [length 3 / frequency 1] baa=c.

Step 2

Rewriting system is complete. See a, b | baaba=abaab.