Morphocompletion for #2723 ⟨a, b | abbba=abbab⟩

Solved by morph:7/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: trailTotalLimit

#Rule
1. abbab ⇒ abbba
2. abbbabab ⇒ abbbabba
3. abbbabbbaab ⇒ abbbabbbaba
4. abbbabbbabbaab ⇒ abbbabbbabbbaa
5. abbbabbbabbbabaab ⇒ abbbabbbabbbabbaa
6. abbbabbbabbbabbbaaab ⇒ abbbabbbabbbabbbabaa
7. abbbabbbabbbabbbabbaaab ⇒ abbbabbbabbbabbbabbbaaa
8. abbbabbbabbbabbbabbbabaaab ⇒ abbbabbbabbbabbbabbbabbaaa
9. abbbabbbabbbabbbabbbabbbaaaab ⇒ abbbabbbabbbabbbabbbabbbabaaa
10. abbbabbbabbbabbbabbbabbbabbaaaab ⇒ abbbabbbabbbabbbabbbabbbabbbaaaa
11. abbbabbbabbbabbbabbbabbbabbbabaaaab ⇒ abbbabbbabbbabbbabbbabbbabbbabbaaaa
12. abbbabbbabbbabbbabbbabbbabbbabbbaaaaab ⇒ abbbabbbabbbabbbabbbabbbabbbabbbabaaaa
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb100lf:100,rf:108
[2/1]ab92lf:68,lp:12,ls:12,rf:60,rp:12,lprp:12,lsrp:12
[2/2]ba56lf:56,rf:60,rs:3
[2/3]aa22lf:22,rf:18,rs:9,a:2
[3/0]abb64lf:52,lp:12,rf:56,rp:12,lprp:12
[3/1]bba52lf:52,rf:56,rs:2
[3/2]bab48lf:46,ls:2,rf:48
[3/3]bbb48lf:48,rf:52
[3/4]aab20lf:10,ls:10,a:2
[3/5]aaa12lf:12,rf:9,rs:6,a:5
[3/6]baa10lf:10,rf:9,rs:3,a:2
[4/0]abbb59lf:48,lp:11,rf:52,rp:12,lprp:11
[4/1]bbba48lf:48,rf:52,rs:1
[4/2]bbab46lf:45,ls:1,rf:48
[4/3]babb40lf:40,rf:44,a:1
[4/4]aaab14lf:7,ls:7,a:5
[4/5]baaa7lf:7,rf:6,rs:3,a:5
[4/6]bbaa7lf:7,rf:6,rs:2,a:2
[5/0]abbba59lf:48,lp:11,rf:52,rp:12,rs:1,re:1,lprp:11
[5/1]bbbab44lf:44,rf:48,a:1
[5/2]bbabb40lf:40,rf:44,a:1
[5/3]babbb37lf:37,rf:40,a:2
[5/4]aaaab8lf:4,ls:4,a:8
[5/5]baaab6lf:3,ls:3,a:5
[5/6]bbaaa5lf:5,rf:4,rs:2,a:5
[6/0]abbbab55lf:44,lp:11,rf:48,rp:11,lprp:11,a:1
[6/1]bbbabb40lf:40,rf:44,a:1
[6/2]babbba37lf:37,rf:40,a:2
[6/3]bbabbb37lf:37,rf:40,a:2
[6/4]baaaab6lf:3,ls:3,a:8
[6/5]abbbaa4lf:4,rf:3,rs:1,a:2
[6/6]bbaaab4lf:2,ls:2,a:5
[7/0]abbbabb50lf:40,lp:10,rf:44,rp:11,lprp:10,a:1
[7/1]bbabbba37lf:37,rf:40,a:2
[7/2]bbbabbb37lf:37,rf:40,a:2
[7/3]babbbab33lf:33,rf:37,a:2
[7/4]abbbaba5lf:4,lp:1,rf:4,rs:1,a:1
[7/5]babbbaa4lf:4,rf:3,rs:1,a:2
[7/6]bbaaaab4lf:2,ls:2,a:8

Considering [length 7 / frequency 0] abbbabb=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbba=abbab⟩.