Morphocompletion for #2710 ⟨a, b | abbab=ababa⟩

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbab ⇒ ababa
2. abababab ⇒ ababaaba
3. abababaaba ⇒ ababaabaab
4. ababaababab ⇒ ababaabaaba
5. ababaabaabab ⇒ ababaabaaaba
6. ababaababaaba ⇒ ababaabaabaab
7. ababaabaabaaba ⇒ ababaabaaabaab
8. ababaabaabbbab ⇒ ababaabaaabaaa
9. ababaabaaababab ⇒ ababaabaaabaaba
10. ababaabaabaaaba ⇒ ababaabaaabaabb
11. ababaabaabbaaba ⇒ ababaabaaabaaab
...

Collecting factors up to length 8 / frequency 7:

[2/0]ab68lf:51,lp:11,ls:6,rf:46,rp:11,rs:4,lprp:11,lsrp:6,lprs:4
[2/1]ba50lf:45,ls:5,rf:41,rs:5
[2/2]aa21lf:21,rf:33,rs:1,a:1
[2/3]bb4lf:4,rf:1,rs:1
[3/0]aba57lf:42,lp:10,ls:5,rf:41,rp:11,rs:5,lprp:10,lsrp:5,lprs:4
[3/1]bab27lf:21,ls:6,rf:11
[3/2]baa19lf:19,rf:25,a:1
[3/3]aab19lf:19,rf:24,rs:4,a:1
[3/4]abb4lf:3,lp:1,rf:1,rs:1
[3/5]bba3lf:3
[3/6]aaa2lf:2,rf:8,rs:1,a:5
[4/0]abab33lf:19,lp:10,ls:4,rf:11,rp:11,lprp:10,lsrp:4
[4/1]aaba22lf:17,ls:5,rf:19,rs:4,a:1
[4/2]abaa18lf:18,rf:25,a:1
[4/3]baab17lf:17,rf:17,rs:3,a:1
[4/4]baba15lf:15,rf:11,rs:1
[4/5]bbab4lf:2,ls:2
[4/6]abba3lf:2,lp:1
[5/0]ababa25lf:15,lp:10,rf:11,rp:11,rs:1,re:1,lprp:10
[5/1]baaba19lf:15,ls:4,rf:13,rs:3,a:1
[5/2]abaab16lf:16,rf:17,rs:3,a:1
[5/3]babaa10lf:10,rf:10,a:1
[5/4]babab8lf:5,ls:3,a:1
[5/5]aabaa8lf:8,rf:15,a:2
[5/6]aabab5lf:4,ls:1,a:2
[6/0]ababaa18lf:10,lp:8,rf:10,rp:10,lprp:8,a:1
[6/1]abaaba17lf:14,ls:3,rf:13,rs:3,a:1
[6/2]babaab10lf:10,rf:10,a:1
[6/3]ababab10lf:5,lp:2,ls:3,a:1
[6/4]baabaa8lf:8,rf:10,a:2
[6/5]aabaab6lf:6,rf:7,rs:3,a:2
[6/6]baabab4lf:3,ls:1,a:2
[7/0]ababaab18lf:10,lp:8,rf:10,rp:10,lprp:8,a:1
[7/1]babaaba12lf:10,ls:2,rf:10,rs:1,a:1
[7/2]abaabaa8lf:8,rf:10,a:2
[7/3]baabaab6lf:6,rf:4,rs:2,a:2
[7/4]aabaaba5lf:4,ls:1,rf:3,rs:2,a:2
[7/5]abababa4lf:2,lp:2,a:1
[7/6]abaabab4lf:3,ls:1,a:2

Considering [length 2 / frequency 0] ab=c.

Step 2

Rewriting system is complete. See ⟨a, b | abbab=ababa⟩.