| Back: | ⟨a, b | abaab=aabba⟩ |
|---|
Solved by morph:5/3,3/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: arenaTotalLimit
| # | Rule |
|---|---|
| 1. | abaab ⇒ aabba |
| 2. | abaaabba ⇒ aabbaaab |
| 3. | aabbaaabbaab ⇒ aabbaaababba |
| 4. | aabbabaaababba ⇒ aabbaabbaaabab |
| 5. | aabbaaabbaaabba ⇒ aabbaaababbaaab |
| 6. | aabbababaaababba ⇒ aabbaabbabaaabab |
| 7. | aabbaaabbaaababba ⇒ aabbaaababbaaabab |
| 8. | aabbaabbaaababbaab ⇒ aabbaabbaaabababba |
| 9. | aabbabababaaababba ⇒ aabbaabbababaaabab |
| ... |
Collecting factors up to length 7, frequency 4:
| Length 2: | [2/0] ab, [2/1] aa, [2/2] ba, [2/3] bb |
|---|---|
| Length 3: | [3/0] aab, [3/1] bba, [3/2] abb, [3/3] aba |
| Length 4: | [4/0] abba, [4/1] aabb, [4/2] baaa, [4/3] aaab |
| Length 5: | [5/0] aabba, [5/1] baaab, [5/2] abbaa, [5/3] babba |
| Length 6: | [6/0] aabbaa, [6/1] ababba, [6/2] aaabba, [6/3] abbaaa |
Considering [length 5 / frequency 3] babba=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | cbba ⇒ babc |
| 2. | babba ⇒ c |
| 3. | cbaab ⇒ cabba |
| 4. | abaab ⇒ aabba |
| 5. | cbabaac ⇒ cbaacba |
| 6. | ababaac ⇒ abaacba |
| 7. | cabbaabba ⇒ cbaac |
| 8. | cbaaabba ⇒ cabbaaab |
| 9. | cbaacabba ⇒ cabbabaac |
| 10. | aabbaabba ⇒ abaac |
| 11. | abaaabba ⇒ aabbaaab |
| 12. | abaacabba ⇒ aabbabaac |
| 13. | cabbaaabbba ⇒ cbaaabc |
| 14. | cabbaabaac ⇒ cabbaaacba |
| 15. | cbaacabaac ⇒ cbaacaacba |
| 16. | aabbaaabbba ⇒ abaaabc |
| 17. | aabbaabaac ⇒ aabbaaacba |
| 18. | abaacabaac ⇒ abaacaacba |
| 19. | cabbaaabbaab ⇒ cabbaaac |
| 20. | cabbabaaacba ⇒ cbaacaac |
| ... |
Collecting factors up to length 6, frequency 7:
| Length 2: | [2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb, [2/4] ac, [2/5] ca, [2/6] cb |
|---|---|
| Length 3: | [3/0] bba, [3/1] baa, [3/2] aab, [3/3] abb, [3/4] aba, [3/5] aac, [3/6] cab |
| Length 4: | [4/0] abba, [4/1] baac, [4/2] abaa, [4/3] aabb, [4/4] cabb, [4/5] baab, [4/6] cbaa |
| Length 5: | [5/0] abaac, [5/1] aabba, [5/2] cabba, [5/3] abbaa, [5/4] bbaab, [5/5] baaab, [5/6] aaabb |
Considering [length 3 / frequency 1] baa=d.
Rewriting system is complete. See ⟨a, b | abaab=aabba⟩.