| Back: | ⟨a, b | abba=bab⟩ |
|---|
Solved by morph:2/1,2/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abba ⇒ bab |
| 2. | babbba ⇒ abbbab |
| 3. | aabbbabb ⇒ babbbba |
| 4. | babbbbaa ⇒ aabbbbab |
| 5. | babbbbaba ⇒ ababbbbab |
| 6. | abaabbbbab ⇒ babbbbbaa |
| 7. | abbbabbbba ⇒ bbabbbbab |
| 8. | abababbbbab ⇒ babbbbbaba |
| 9. | abbbabbbbba ⇒ bbbabbbbab |
| 10. | babbbbbaaba ⇒ abaabbbbbab |
| 11. | abaababbbbab ⇒ babbbbbabaa |
| ... |
Collecting factors up to length 7, frequency 4:
| Length 2: | [2/0] bb, [2/1] ba, [2/2] ab, [2/3] aa |
|---|---|
| Length 3: | [3/0] bbb, [3/1] bab, [3/2] abb, [3/3] bba |
| Length 4: | [4/0] bbba, [4/1] babb, [4/2] abbb, [4/3] bbbb |
| Length 5: | [5/0] babbb, [5/1] bbbba, [5/2] bbbab, [5/3] abbbb |
| Length 6: | [6/0] babbbb, [6/1] bbbbab, [6/2] abbbba, [6/3] abbbab |
Considering [length 2 / frequency 1] ba=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | ba ⇒ c |
| 2. | abc ⇒ cb |
| 3. | bcb ⇒ cbc |
| 4. | cbca ⇒ bcc |
| 5. | acbc ⇒ cbb |
| 6. | cbcca ⇒ bbcc |
| 7. | accbc ⇒ cbbb |
| 8. | abbcc ⇒ cbbca |
| 9. | bccbc ⇒ cbccb |
| 10. | cbccca ⇒ bbbcc |
| 11. | acccbc ⇒ cbbbb |
| 12. | acbbcc ⇒ cbbbca |
| 13. | abbbcc ⇒ cbbcca |
| 14. | bcccbc ⇒ cbccbb |
| 15. | cbcccca ⇒ bbbbcc |
| 16. | accccbc ⇒ cbbbbb |
| 17. | accbbcc ⇒ cbbbbca |
| 18. | acbbbcc ⇒ cbbbcca |
| 19. | abbbbcc ⇒ cbbccca |
| 20. | bccccbc ⇒ cbccbbb |
| ... |
Collecting factors up to length 6, frequency 7:
| Length 2: | [2/0] bc, [2/1] cc, [2/2] cb, [2/3] ac, [2/4] bb, [2/5] ab, [2/6] ca |
|---|---|
| Length 3: | [3/0] cbc, [3/1] bcc, [3/2] ccc, [3/3] acc, [3/4] ccb, [3/5] bbc, [3/6] abb |
| Length 4: | [4/0] bbcc, [4/1] ccbc, [4/2] bccc, [4/3] cbcc, [4/4] abbb, [4/5] acbb, [4/6] accb |
| Length 5: | [5/0] cccbc, [5/1] bbbcc, [5/2] cbbcc, [5/3] cbccc, [5/4] bcccc, [5/5] bcccb, [5/6] bccca |
Considering [length 2 / frequency 0] bc=d.
Rewriting system is complete. See ⟨a, b | abba=bab⟩.