Morphocompletion for #2624 ⟨a, b | abbaab=bbaa⟩

Solved by morph:4/0,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbaab ⇒ bbaa
2. abbabbaa ⇒ bbaabaab
3. aabbbbaa ⇒ bbaaaabb
4. bbaabaabb ⇒ abbbbaa
5. abbbbaaaab ⇒ bbaababbaa
6. abbbbaaabbaa ⇒ bbaabbbaaaab
7. aabbbbbbaaaa ⇒ bbbbaaaaaabb
8. aaabbbbabbaa ⇒ bbaabaaaabbb
9. bbaabbbaaaabb ⇒ abbbbaabbaa
10. bbaabbaaaabbb ⇒ aabbbbabbaa
...

Collecting factors up to length 7 / frequency 4:

[2/0]bb38lf:32,lp:3,ls:3,rf:27,rp:7,rs:3
[2/1]aa35lf:27,lp:3,ls:5,rf:26,rp:1,rs:5
[2/2]ab24lf:18,lp:4,ls:2,rf:15,rp:2,rs:2,lprs:2
[2/3]ba16lf:16,rf:17
[3/0]abb21lf:15,lp:4,ls:2,rf:10,rp:2,rs:2,lsrp:2
[3/1]bba18lf:15,lp:3,rf:14,rp:6
[3/2]baa18lf:14,ls:4,rf:15,rs:5
[3/3]aab16lf:12,lp:2,ls:2,rf:11,rp:1,rs:2
[4/0]bbaa20lf:13,lp:3,ls:4,rf:13,rp:6,rs:5,re:1,lsrp:4,lprs:3
[4/1]aabb13lf:9,lp:2,ls:2,rf:6,rp:1,rs:2,lprs:2,a:2
[4/2]abbb10lf:7,lp:2,ls:1,rf:5,rp:2,rs:1,a:2
[4/3]abba8lf:6,lp:2,rf:3
[5/0]abbaa9lf:5,lp:1,ls:3,rf:3,rs:3
[5/1]aabbb8lf:5,lp:2,ls:1,rf:3,rp:1,rs:1,lsrp:1,a:3
[5/2]bbaab8lf:4,lp:3,ls:1,rf:5,rp:4
[5/3]abbbb7lf:5,lp:2,rf:3,rp:2,a:2
[6/0]abbbba6lf:4,lp:2,rf:3,rp:2,a:2
[6/1]aabbbb5lf:3,lp:2,rf:1,rp:1,a:3
[6/2]bbbbaa5lf:4,ls:1,rf:3,rp:1,rs:1,a:2
[6/3]bbaaaa5lf:4,ls:1,rf:3,rp:1,a:3

Considering [length 4 / frequency 0] bbaa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. caa ⇒ aacc
2. cbaa ⇒ acc
3. acb ⇒ c
4. acccb ⇒ cbac
5. acccccb ⇒ cbcac
6. acccccccb ⇒ cbccac
7. bbac ⇒ ccb
8. bbcac ⇒ ccccb
9. bbccac ⇒ ccccccb
10. bbcccac ⇒ ccccccccb
11. bbaa ⇒ c
12. ccbb ⇒ bbc
13. bbcbac ⇒ ccbccb
14. bbcbcac ⇒ ccbccccb
15. bbccbac ⇒ ccccbccb
16. bbcbcbac ⇒ ccbccbccb
17. bbabbc ⇒ ccbcbb
18. bbcabbc ⇒ ccccbcbb
19. bbcbabbc ⇒ ccbccbcbb
20. bbabbbbc ⇒ ccbcbbcbb
...

Collecting factors up to length 6 / frequency 7:

[2/0]bb34lf:20,lp:13,ls:1,rf:6,rp:1,rs:4,lsrp:1,lprs:4,a:1
[2/1]ac24lf:12,lp:4,ls:8,rf:5,rp:1,rs:3,lprs:3,a:2
[2/2]bc19lf:15,ls:4,rf:14,rs:1,a:7
[2/3]cc18lf:17,lp:1,rf:39,rp:12,rs:2,a:3
[2/4]cb17lf:12,lp:1,ls:4,rf:26,rp:3,rs:8,lsrp:3,a:2
[2/5]ba9lf:9,rf:1,a:1
[2/6]ca7lf:6,lp:1,rf:2,a:5
[3/0]bbc26lf:13,lp:9,ls:4,rf:2,rp:1,rs:1,re:1,a:7
[3/1]ccc10lf:10,rf:18,rp:5,a:6
[3/2]ccb9lf:5,lp:1,ls:3,rf:18,rp:7,rs:8,re:1,a:3
[3/3]bba8lf:4,lp:4,a:1
[3/4]bac8lf:4,ls:4,rf:1,rs:1,a:3
[3/5]cac8lf:4,ls:4,rf:2,rs:2,a:9
[3/6]cba6lf:5,lp:1,rf:1,rp:1,a:4
[4/0]bbcb8lf:4,lp:4,rf:1,a:10
[4/1]abbc6lf:3,ls:3,a:8
[4/2]bbcc6lf:3,lp:3,a:12
[4/3]cccb6lf:3,ls:3,rf:6,rs:4,a:6
[4/4]cbac6lf:3,ls:3,rf:1,rp:1,rs:1,re:1,a:6
[4/5]accc6lf:3,lp:3,a:6
[4/6]cccc6lf:6,rf:12,rp:5,a:9
[5/0]bbabb4lf:2,lp:2,a:8
[5/1]babbc4lf:2,ls:2,a:8
[5/2]bbcba4lf:2,lp:2,a:10
[5/3]bbcbc4lf:2,lp:2,a:13
[5/4]bcbac4lf:2,ls:2,a:10
[5/5]ccccb4lf:2,ls:2,rf:6,rp:3,rs:4,re:1,a:9
[5/6]acccc4lf:2,lp:2,a:11

Considering [length 2 / frequency 0] bb=d.

Step 3

Rewriting system is complete. See ⟨a, b | abbaab=bbaa⟩.