Morphocompletion for #2608 ⟨a, b | ababba=baab

Solved by morph:3/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. ababba ⇒ baab
2. baabbabba ⇒ ababbbaab
3. ababababbbaab ⇒ babaabbba
4. ababababbbabaab ⇒ babaabbbaabba
5. baabbabababbbaab ⇒ ababbbabaabbba
6. babaabbbaabbaabba ⇒ ababababbbababaab
7. ababbbabaabbbaabba ⇒ baabbabababbbabaab
8. ababababbbaaababbbaab ⇒ babaabbbaaabbabba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] bb, [2/3] aa
Length 3:[3/0] aba, [3/1] bab, [3/2] bba, [3/3] aab, [3/4] abb, [3/5] baa, [3/6] bbb
Length 4:[4/0] abab, [4/1] baab, [4/2] baba, [4/3] abba, [4/4] bbba, [4/5] babb, [4/6] abbb
Length 5:[5/0] ababa, [5/1] bbaab, [5/2] baabb, [5/3] ababb, [5/4] abbba, [5/5] babab, [5/6] aabba
Length 6:[6/0] ababab, [6/1] baabba, [6/2] bbbaab, [6/3] ababbb, [6/4] babbba, [6/5] abbbaa, [6/6] babaab
Length 7:[7/0] abbbaab, [7/1] ababbba, [7/2] abababa, [7/3] bbaabba, [7/4] bababbb, [7/5] babbbaa, [7/6] bababab

Considering [length 3 / frequency 2] bba=c.

Step 2

Rewriting system is complete. See a, b | ababba=baab.