| Back: | ⟨a, b | ababba=abab⟩ |
|---|
Solved by morph:5/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | ababba ⇒ abab |
| 2. | ababbba ⇒ ababb |
| 3. | ababbbba ⇒ ababbb |
| 4. | ababbbbba ⇒ ababbbb |
| 5. | ababbbbbba ⇒ ababbbbb |
| 6. | ababbbbbbba ⇒ ababbbbbb |
| 7. | ababbbbbbbba ⇒ ababbbbbbb |
| 8. | ababbbbbbbbba ⇒ ababbbbbbbb |
| 9. | ababbbbbbbbbba ⇒ ababbbbbbbbb |
| 10. | ababbbbbbbbbbba ⇒ ababbbbbbbbbb |
| 11. | ababbbbbbbbbbbba ⇒ ababbbbbbbbbbb |
| 12. | ababbbbbbbbbbbbba ⇒ ababbbbbbbbbbbb |
| 13. | ababbbbbbbbbbbbbba ⇒ ababbbbbbbbbbbbb |
| 14. | ababbbbbbbbbbbbbbba ⇒ ababbbbbbbbbbbbbb |
| 15. | ababbbbbbbbbbbbbbbba ⇒ ababbbbbbbbbbbbbbb |
| 16. | ababbbbbbbbbbbbbbbbba ⇒ ababbbbbbbbbbbbbbbb |
| 17. | ababbbbbbbbbbbbbbbbbba ⇒ ababbbbbbbbbbbbbbbbb |
| 18. | ababbbbbbbbbbbbbbbbbbba ⇒ ababbbbbbbbbbbbbbbbbb |
| 19. | ababbbbbbbbbbbbbbbbbbbba ⇒ ababbbbbbbbbbbbbbbbbbb |
| 20. | ababbbbbbbbbbbbbbbbbbbbba ⇒ ababbbbbbbbbbbbbbbbbbbb |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | bb | 210 | lf:210,rf:190,rs:19 |
|---|---|---|---|
| [2/1] | ba | 60 | lf:40,ls:20,rf:20 |
| [2/2] | ab | 60 | lf:40,lp:20,rf:40,rp:20,rs:1,lprp:20,lprs:1 |
| [3/0] | bbb | 190 | lf:190,rf:171,rs:18,a:1 |
| [3/1] | bba | 40 | lf:20,ls:20 |
| [3/2] | aba | 40 | lf:20,lp:20,rf:20,rp:20,lprp:20 |
| [3/3] | bab | 20 | lf:20,rf:20,rs:1 |
| [3/4] | abb | 20 | lf:20,rf:19,rs:1 |
| [4/0] | bbbb | 171 | lf:171,rf:153,rs:17,a:2 |
| [4/1] | abab | 40 | lf:20,lp:20,rf:20,rp:20,rs:1,re:1,lprp:20,lprs:1 |
| [4/2] | bbba | 38 | lf:19,ls:19,a:1 |
| [4/3] | babb | 20 | lf:20,rf:19,rs:1 |
| [4/4] | abbb | 19 | lf:19,rf:18,rs:1,a:1 |
| [4/5] | abba | 2 | lf:1,ls:1 |
| [5/0] | bbbbb | 153 | lf:153,rf:136,rs:16,a:3 |
| [5/1] | ababb | 40 | lf:20,lp:20,rf:19,rp:19,rs:1,re:1,lprp:19,lprs:1 |
| [5/2] | bbbba | 36 | lf:18,ls:18,a:2 |
| [5/3] | babbb | 19 | lf:19,rf:18,rs:1,a:1 |
| [5/4] | abbbb | 18 | lf:18,rf:17,rs:1,a:2 |
| [5/5] | babba | 2 | lf:1,ls:1 |
| [5/6] | abbba | 2 | lf:1,ls:1,a:1 |
| [6/0] | bbbbbb | 136 | lf:136,rf:120,rs:15,a:4 |
| [6/1] | ababbb | 38 | lf:19,lp:19,rf:18,rp:18,rs:1,re:1,lprp:18,lprs:1,a:1 |
| [6/2] | bbbbba | 34 | lf:17,ls:17,a:3 |
| [6/3] | babbbb | 18 | lf:18,rf:17,rs:1,a:2 |
| [6/4] | abbbbb | 17 | lf:17,rf:16,rs:1,a:3 |
| [6/5] | babbba | 2 | lf:1,ls:1,a:1 |
| [6/6] | abbbba | 2 | lf:1,ls:1,a:2 |
| [7/0] | bbbbbbb | 120 | lf:120,rf:105,rs:14,a:5 |
| [7/1] | ababbbb | 36 | lf:18,lp:18,rf:17,rp:17,rs:1,re:1,lprp:17,lprs:1,a:2 |
| [7/2] | bbbbbba | 32 | lf:16,ls:16,a:4 |
| [7/3] | babbbbb | 17 | lf:17,rf:16,rs:1,a:3 |
| [7/4] | abbbbbb | 16 | lf:16,rf:15,rs:1,a:4 |
| [7/5] | babbbba | 2 | lf:1,ls:1,a:2 |
| [7/6] | abbbbba | 2 | lf:1,ls:1,a:3 |
Considering [length 5 / frequency 1] ababb=c.
Rewriting system is complete. See ⟨a, b | ababba=abab⟩.