Morphocompletion for #2598 ⟨a, b | ababab=bbaa

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. ababab ⇒ bbaa
2. bbaaab ⇒ abbbaa
3. ababaabbbaa ⇒ bbaabaaab
4. bbaaaabbbaa ⇒ abbbaabaaab
5. ababaababbbaa ⇒ bbaabaaabab
6. bbaaaababbbaa ⇒ abbbaabaaabab
7. bbaabaaabbabab ⇒ ababaabbbabbaa
8. bbaabaaababbabab ⇒ ababaababbbabbaa
9. ababaababaabbbabbaa ⇒ bbaabaabaaabbabab
10. bbaaaababaabbbabbaa ⇒ abbbaabaabaaabbabab
11. bbaabaaabbabaabbbaa ⇒ ababaabbbabbaabaaab
12. ababaababaababbbabbaa ⇒ bbaabaabaaababbabab
13. bbaaaababaababbbabbaa ⇒ abbbaabaabaaababbabab
14. bbaabaaababbabaabbbaa ⇒ ababaababbbabbaabaaab
15. bbaabaaabbabaababbbaa ⇒ ababaabbbabbaabaaabab
16. bbaabaabaaabbababbabab ⇒ ababaababaabbbabbabbaa
17. bbaabaaababbabaababbbaa ⇒ ababaababbbabbaabaaabab
18. bbaabaabaaababbababbabab ⇒ ababaababaababbbabbabbaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] baa, [3/1] aba, [3/2] bba, [3/3] bab, [3/4] aab, [3/5] abb, [3/6] aaa
Length 4:[4/0] bbaa, [4/1] abab, [4/2] aaba, [4/3] abaa, [4/4] baab, [4/5] baba, [4/6] babb
Length 5:[5/0] baaba, [5/1] bbbaa, [5/2] bbaab, [5/3] ababa, [5/4] abaab, [5/5] aabab, [5/6] babaa
Length 6:[6/0] bbaaba, [6/1] abbbaa, [6/2] ababaa, [6/3] babaab, [6/4] baabaa, [6/5] abbaba, [6/6] aababb
Length 7:[7/0] bbaabaa, [7/1] ababaab, [7/2] abbabab, [7/3] baabaaa, [7/4] aabaaab, [7/5] bbaaaab, [7/6] aabbbaa

Considering [length 2 / frequency 0] ab=c.

Step 2

Rewriting system is complete. See a, b | ababab=bbaa.