Morphocompletion for #2597 ⟨a, b | ababab=baba

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababab ⇒ baba
2. babaab ⇒ abbaba
3. bbabaaab ⇒ abbbabaa
4. abaabbaba ⇒ babaaab
5. babaaabbab ⇒ abaabbbaba
6. bbabaaaabb ⇒ aabbbbabaa
7. abaababbaba ⇒ babaaabab
8. babaaababbab ⇒ abaababbbaba
9. aabbababbabaa ⇒ bbabaaaab
10. abaaabbbabaa ⇒ babaaabaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] baa, [3/3] aab, [3/4] bba, [3/5] abb, [3/6] aaa
Length 4:[4/0] baba, [4/1] abaa, [4/2] bbab, [4/3] abab, [4/4] aabb, [4/5] aaab, [4/6] abba
Length 5:[5/0] babaa, [5/1] bbaba, [5/2] abbab, [5/3] abaaa, [5/4] abaab, [5/5] baaab, [5/6] aabba
Length 6:[6/0] bbabaa, [6/1] babaaa, [6/2] abaaab, [6/3] abbaba, [6/4] aabbab, [6/5] babbab, [6/6] ababba
Length 7:[7/0] babaaab, [7/1] bbabaaa, [7/2] aabbaba, [7/3] ababbab, [7/4] abaaabb, [7/5] babbaba, [7/6] baaaabb

Considering [length 2 / frequency 0] ab=c.

Step 2

Rewriting system is complete. See a, b | ababab=baba.