| Back: | ⟨a, b | ababab=baba⟩ |
|---|
Solved by morph:2/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | ababab ⇒ baba |
| 2. | babaab ⇒ abbaba |
| 3. | bbabaaab ⇒ abbbabaa |
| 4. | abaabbaba ⇒ babaaab |
| 5. | babaaabbab ⇒ abaabbbaba |
| 6. | bbabaaaabb ⇒ aabbbbabaa |
| 7. | abaababbaba ⇒ babaaabab |
| 8. | aabbababbabaa ⇒ bbabaaaab |
| 9. | abaaabbbabaa ⇒ babaaabaab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 34 | lf:26,lp:4,ls:4,rf:20,rp:3,rs:4,lsrp:3,lprs:3 |
|---|---|---|---|
| [2/1] | ba | 29 | lf:25,lp:2,ls:2,rf:21,rp:4,rs:3,lsrp:2,lprs:2 |
| [2/2] | aa | 18 | lf:15,lp:1,ls:2,rf:14,rp:1,rs:2,a:1 |
| [2/3] | bb | 13 | lf:10,lp:2,ls:1,rf:9,rp:1,a:1 |
| [3/0] | aba | 21 | lf:15,lp:4,ls:2,rf:12,rp:1,rs:3,lprs:1 |
| [3/1] | bab | 18 | lf:14,lp:2,ls:2,rf:10,rp:4,rs:1,lsrp:1 |
| [3/2] | baa | 11 | lf:9,ls:2,rf:8,rs:2,a:1 |
| [3/3] | aab | 11 | lf:8,lp:1,ls:2,rf:7,rp:1,rs:3,lprs:1,a:1 |
| [3/4] | bba | 10 | lf:8,lp:2,rf:5,rp:1,a:1 |
| [3/5] | abb | 8 | lf:7,ls:1,rf:4,rp:2,a:1 |
| [3/6] | aaa | 5 | lf:5,rf:5,a:2 |
| [4/0] | abaa | 14 | lf:9,lp:3,ls:2,rf:8,rp:1,rs:2,a:1 |
| [4/1] | baba | 14 | lf:10,lp:2,ls:2,rf:9,rp:4,rs:3,re:1,lsrp:2,lprs:2 |
| [4/2] | bbab | 11 | lf:8,lp:2,ls:1,rf:5,rp:1,a:1 |
| [4/3] | aabb | 7 | lf:5,lp:1,ls:1,rf:2,rp:1,lsrp:1,a:2 |
| [4/4] | abab | 6 | lf:4,lp:1,ls:1,rf:1,rs:1 |
| [4/5] | aaab | 5 | lf:4,ls:1,rf:4,rs:2,a:2 |
| [4/6] | abba | 5 | lf:5,rf:1,rp:1,a:1 |
| [5/0] | bbaba | 11 | lf:7,lp:2,ls:2,rf:5,rp:1,rs:2,a:1 |
| [5/1] | babaa | 10 | lf:6,lp:2,ls:2,rf:6,rp:3,rs:2,lsrp:1,a:1 |
| [5/2] | abaab | 6 | lf:3,lp:2,ls:1,rf:2,rp:1,rs:1,a:1 |
| [5/3] | abbab | 6 | lf:5,ls:1,rf:1,rp:1,a:1 |
| [5/4] | abaaa | 5 | lf:4,lp:1,rf:4,a:2 |
| [5/5] | baaab | 4 | lf:3,ls:1,rf:3,rs:1,a:2 |
| [5/6] | aabba | 4 | lf:3,lp:1,a:2 |
| [6/0] | bbabaa | 8 | lf:4,lp:2,ls:2,rf:3,rp:1,rs:2,lsrp:1,lprs:2,a:4 |
| [6/1] | abbaba | 6 | lf:4,ls:2,rf:1,rp:1,rs:1,re:1,a:1 |
| [6/2] | abaaab | 5 | lf:3,lp:1,ls:1,rf:3,rs:1,a:2 |
| [6/3] | aabbab | 5 | lf:3,lp:1,ls:1,a:2 |
| [6/4] | babaaa | 4 | lf:3,lp:1,rf:4,rp:3,a:2 |
| [6/5] | abaaba | 2 | lf:1,lp:1,a:7 |
| [6/6] | aaaabb | 2 | lf:1,ls:1,a:29 |
| [7/0] | bbabaaa | 4 | lf:2,lp:2,rf:1,rp:1,a:4 |
| [7/1] | babaaab | 4 | lf:2,lp:1,ls:1,rf:3,rp:3,rs:1,re:1,a:2 |
| [7/2] | aabbaba | 4 | lf:2,lp:1,ls:1,a:2 |
| [7/3] | abaaabb | 3 | lf:2,lp:1,a:6 |
| [7/4] | babbaba | 3 | lf:2,ls:1,a:5 |
| [7/5] | baaaabb | 2 | lf:1,ls:1,a:29 |
| [7/6] | abbabaa | 2 | lf:1,ls:1,a:5 |
Considering [length 2 / frequency 0] ab=c.
Rewriting system is complete. See ⟨a, b | ababab=baba⟩.