| Back: | ⟨a, b | ababab=abba⟩ |
|---|
Solved by morph:4/0,2/2. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: trailTotalLimit
| # | Rule |
|---|---|
| 1. | ababab ⇒ abba |
| 2. | abbaab ⇒ ababba |
| 3. | abbabaab ⇒ ababbaba |
| 4. | abbababaab ⇒ ababbababa |
| 5. | abbabbaaab ⇒ ababbabbaa |
| 6. | abbababbaaab ⇒ ababbababbaa |
| 7. | abbabbabaaab ⇒ ababbabbabaa |
| 8. | abbababbabaaab ⇒ ababbababbabaa |
| 9. | abbabbababaaab ⇒ ababbabbababaa |
| 10. | abbabbabbaaaab ⇒ ababbabbabbaaa |
| 11. | ababbabbabbaaaab ⇒ abbababbabbaaa |
| 12. | abbababbababaaab ⇒ ababbababbababaa |
| 13. | abbababbabbaaaab ⇒ ababbababbabbaaa |
| 14. | abbabbababbaaaab ⇒ ababbabbababbaaa |
| ... |
Collecting factors up to length 7, frequency 4:
| Length 2: | [2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb |
|---|---|
| Length 3: | [3/0] abb, [3/1] bab, [3/2] bba, [3/3] aab |
| Length 4: | [4/0] abba, [4/1] aaab, [4/2] bbab, [4/3] baba |
| Length 5: | [5/0] abbab, [5/1] babba, [5/2] baaab, [5/3] bbaba |
| Length 6: | [6/0] abbaba, [6/1] abbabb, [6/2] bbabba, [6/3] babbab |
Considering [length 4 / frequency 0] abba=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | cccb ⇒ cbc |
| 2. | cbccb ⇒ cbbc |
| 3. | abccb ⇒ abbc |
| 4. | cab ⇒ abc |
| 5. | cbaccb ⇒ cbabc |
| 6. | cbba ⇒ abbc |
| 7. | cbca ⇒ cbacc |
| 8. | ccba ⇒ cbac |
| 9. | cbbca ⇒ abbccc |
| 10. | cbcba ⇒ abbcc |
| 11. | ababc ⇒ cba |
| 12. | ababbc ⇒ cbacb |
| 13. | abba ⇒ c |
| 14. | abbca ⇒ ccc |
| 15. | abcba ⇒ cc |
| 16. | abbcba ⇒ cbabc |
| 17. | abbcca ⇒ ccccc |
| 18. | cbaab ⇒ cc |
| 19. | cbaba ⇒ abcc |
| 20. | ababab ⇒ c |
| ... |
Collecting factors up to length 6, frequency 7:
| Length 2: | [2/0] ab, [2/1] cb, [2/2] ba, [2/3] bc, [2/4] ca, [2/5] cc, [2/6] bb |
|---|---|
| Length 3: | [3/0] cba, [3/1] ccb, [3/2] aba, [3/3] abb, [3/4] bca, [3/5] bab, [3/6] abc |
| Length 4: | [4/0] abab, [4/1] abbc, [4/2] bcba, [4/3] bbca, [4/4] bccb, [4/5] baba, [4/6] cbaa |
| Length 5: | [5/0] ababa, [5/1] babab, [5/2] ababb, [5/3] bbcca, [5/4] bbcba, [5/5] cbacc, [5/6] baccb |
Considering [length 2 / frequency 2] ba=d.
Rewriting system is complete. See ⟨a, b | ababab=abba⟩.