Morphocompletion for #2580 ⟨a, b | abaaba=aaab⟩

Solved by morph:2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaba ⇒ aaab
2. abaaaab ⇒ aaababa
3. aaabbaaba ⇒ aaabaab
4. aaabbaaaab ⇒ aaaaabba
5. aaababaaaba ⇒ abaaaaaab
6. aaabaabbaaba ⇒ aaaaabab
7. aaaaababbaaba ⇒ aaaaababaab
8. aaabbaaaaaab ⇒ aaaaabbaaaba
9. aaababaaaaab ⇒ abaaaaaababa
10. aaabaabbaaaab ⇒ aaaaabababa
11. aaaaababbaaaab ⇒ aaaaabaaabba
12. aaaaababaabbaaba ⇒ aaaaabaaabab
13. aaabababaaaaaab ⇒ abaaaaaabbaaaba
14. aaabaabbaaaaaab ⇒ aaaaabababaaaba
15. aaaaabbaaabaaaba ⇒ aaabbaaaaaaaab
16. aaaaabaaababbaaba ⇒ aaaaabaaababaab
17. aaaaababbaaaaaab ⇒ aaaaabaaabbaaaba
18. aaaaababaabbaaaab ⇒ aaaaabaaabababa
19. aaaaabbaaabaaaaab ⇒ aaabbaaaaaaaababa
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa131lf:114,lp:17,rf:104,rp:16,lprp:14
[2/1]ab69lf:56,lp:2,ls:11,rf:49,rp:3,rs:8,lsrp:2,lprs:1
[2/2]ba53lf:45,ls:8,rf:41,rs:11
[2/3]bb14lf:14,rf:7,a:2
[3/0]aaa87lf:70,lp:17,rf:71,rp:16,lprp:14
[3/1]aab55lf:44,ls:11,rf:33,rs:6
[3/2]aba41lf:31,lp:2,ls:8,rf:34,rp:3,rs:9,lsrp:1,lprs:1
[3/3]baa27lf:27,rf:17
[3/4]abb14lf:14,rf:7,a:2
[3/5]bba14lf:14,rf:7,rs:2,a:2
[3/6]bab10lf:10,rf:13,rs:2,a:1
[4/0]aaab53lf:33,lp:9,ls:11,rf:30,rp:5,rs:3,re:1,lprp:1,lsrp:2,lprs:1
[4/1]aaaa45lf:37,lp:8,rf:41,rp:11,lprp:6,a:1
[4/2]aaba31lf:23,ls:8,rf:20,rs:4
[4/3]baaa16lf:16,rf:14,a:1
[4/4]abaa15lf:13,lp:2,rf:12,rp:3
[4/5]abba14lf:14,rf:7,rs:2,a:2
[4/6]bbaa14lf:14,rf:5,a:2
[5/0]aaaab30lf:19,ls:11,rf:16,rs:2,a:1
[5/1]aaaaa26lf:18,lp:8,rf:25,rp:11,lprp:6,a:3
[5/2]aaaba25lf:17,lp:6,ls:2,rf:20,rp:2,rs:4,lprs:2,a:1
[5/3]abbaa14lf:14,rf:5,a:2
[5/4]baaba12lf:6,ls:6
[5/5]baaaa11lf:11,rf:5,a:1
[5/6]aabba10lf:10,rf:7,rs:2,a:2
[6/0]aaaaab28lf:14,lp:8,ls:6,rf:16,rp:11,rs:2,lprp:6,lsrp:3,lprs:1,a:3
[6/1]aaabab12lf:9,lp:3,rf:10,rp:1,rs:2,a:1
[6/2]baaaab10lf:5,ls:5,a:1
[6/3]aabbaa10lf:10,rf:5,a:2
[6/4]bbaaba10lf:5,ls:5,a:2
[6/5]aaabaa9lf:6,lp:3,rf:6,rp:1,a:2
[6/6]abbaaa9lf:9,rf:5,a:3
[7/0]aaaaaba12lf:6,lp:6,rf:11,rp:9,lprp:6,a:5
[7/1]abbaaba10lf:5,ls:5,a:2
[7/2]aaaaaab8lf:4,ls:4,rf:5,rs:2,a:4
[7/3]aaababa8lf:5,lp:3,rf:8,rp:1,rs:3,re:1,lprs:1,a:1
[7/4]aaabbaa8lf:5,lp:3,rf:5,rp:2,a:2
[7/5]bbaaaab8lf:4,ls:4,a:3
[7/6]aabbaaa7lf:7,rf:5,a:3

Considering [length 2 / frequency 1] ab=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaaba=aaab⟩.