| Back: | ⟨a, b | abaaab=baab⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abaaab ⇒ baab |
| 2. | abaabaab ⇒ babaab |
| 3. | abababaab ⇒ bbabaab |
| 4. | bbababaab ⇒ abbbabaab |
| 5. | abaababaab ⇒ bababaab |
| 6. | ababbabaab ⇒ bbbabaab |
| 7. | bbabbabaab ⇒ abbbbabaab |
| 8. | abaabbabaab ⇒ babbabaab |
| 9. | ababbbabaab ⇒ bbbbabaab |
| 10. | bbabbbabaab ⇒ abbbbbabaab |
| 11. | abaabbbabaab ⇒ babbbabaab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 57 | lf:38,lp:8,ls:11,rf:27,rp:3,rs:11,lsrp:3,lprs:8,lsrs:11 |
|---|---|---|---|
| [2/1] | ba | 30 | lf:30,rf:24,rp:5 |
| [2/2] | aa | 16 | lf:16,rf:11 |
| [2/3] | bb | 15 | lf:12,lp:3,rf:18,rp:3,a:3 |
| [3/0] | aba | 29 | lf:21,lp:8,rf:11 |
| [3/1] | aab | 26 | lf:15,ls:11,rf:11,rs:11,lsrs:11 |
| [3/2] | bab | 15 | lf:15,rf:13,rp:4,a:1 |
| [3/3] | baa | 15 | lf:15,rf:11,rp:1 |
| [3/4] | bba | 12 | lf:9,lp:3,rf:8,rp:1,a:3 |
| [3/5] | abb | 6 | lf:6,rf:5,rp:3,a:4 |
| [3/6] | bbb | 3 | lf:3,rf:10,rp:2,a:6 |
| [4/0] | baab | 24 | lf:14,ls:10,rf:11,rp:1,rs:11,re:1,lsrs:10 |
| [4/1] | abaa | 20 | lf:15,lp:5,rf:10 |
| [4/2] | bbab | 12 | lf:9,lp:3,rf:8,rp:1,a:3 |
| [4/3] | baba | 11 | lf:11,rf:11,rp:2,a:1 |
| [4/4] | abab | 9 | lf:6,lp:3,rf:1,a:2 |
| [4/5] | babb | 4 | lf:4,rf:2,rp:2,a:4 |
| [4/6] | bbba | 3 | lf:3,rf:6,rp:1,a:6 |
| [5/0] | abaab | 28 | lf:14,lp:4,ls:10,rf:10,rs:10,lprs:4,lsrs:10,a:1 |
| [5/1] | babaa | 9 | lf:9,rf:10,rp:1,a:1 |
| [5/2] | bbaba | 8 | lf:7,lp:1,rf:8,rp:1,a:3 |
| [5/3] | ababa | 5 | lf:4,lp:1,rf:1,a:2 |
| [5/4] | bbabb | 4 | lf:2,lp:2,a:13 |
| [5/5] | ababb | 4 | lf:2,lp:2,a:7 |
| [5/6] | bbbab | 3 | lf:3,rf:6,rp:1,a:6 |
| [6/0] | babaab | 18 | lf:9,ls:9,rf:10,rp:1,rs:10,re:1,lsrs:9,a:1 |
| [6/1] | bbabaa | 6 | lf:6,rf:8,rp:1,a:3 |
| [6/2] | abaabb | 4 | lf:2,lp:2,a:4 |
| [6/3] | abaaba | 4 | lf:2,lp:2,a:1 |
| [6/4] | bbbaba | 3 | lf:3,rf:6,rp:1,a:6 |
| [6/5] | abbbab | 3 | lf:3,rf:2,rp:1,a:6 |
| [6/6] | abbaba | 3 | lf:3,rf:1,a:4 |
| [7/0] | bbabaab | 12 | lf:6,ls:6,rf:8,rp:1,rs:8,re:1,lsrs:6,a:3 |
| [7/1] | ababaab | 6 | lf:3,ls:3,rf:1,rs:1,lsrs:1,a:2 |
| [7/2] | bbbabaa | 3 | lf:3,rf:6,rp:1,a:6 |
| [7/3] | abbbaba | 3 | lf:3,rf:2,rp:1,a:6 |
| [7/4] | abbabaa | 3 | lf:3,rf:1,a:4 |
| [7/5] | bbabbba | 2 | lf:1,lp:1,a:23 |
| [7/6] | bbabbab | 2 | lf:1,lp:1,a:13 |
Considering [length 3 / frequency 0] aba=c.
Rewriting system is complete. See ⟨a, b | abaaab=baab⟩.