Morphocompletion for #2572 ⟨a, b | abaaab=baab⟩

Back:⟨a, b | abaaab=baab⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaab ⇒ baab
2. abaabaab ⇒ babaab
3. abababaab ⇒ bbabaab
4. bbababaab ⇒ abbbabaab
5. abaababaab ⇒ bababaab
6. ababbabaab ⇒ bbbabaab
7. bbabbabaab ⇒ abbbbabaab
8. abaabbabaab ⇒ babbabaab
9. ababbbabaab ⇒ bbbbabaab
10. bbabbbabaab ⇒ abbbbbabaab
11. abaabbbabaab ⇒ babbbabaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] aab, [3/2] bab, [3/3] baa, [3/4] bba, [3/5] abb, [3/6] bbb
Length 4:[4/0] baab, [4/1] abaa, [4/2] bbab, [4/3] baba, [4/4] abab, [4/5] babb, [4/6] bbba
Length 5:[5/0] abaab, [5/1] babaa, [5/2] bbaba, [5/3] ababa, [5/4] bbabb, [5/5] ababb, [5/6] bbbab
Length 6:[6/0] babaab, [6/1] bbabaa, [6/2] abaabb, [6/3] abaaba, [6/4] bbbaba, [6/5] abbbab, [6/6] abbaba
Length 7:[7/0] bbabaab, [7/1] ababaab, [7/2] bbbabaa, [7/3] abbbaba, [7/4] abbabaa, [7/5] bbabbba, [7/6] bbabbab

Considering [length 3 / frequency 0] aba=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaaab=baab⟩.