Morphocompletion for #2565 ⟨a, b | abaaab=aaba⟩

Back:⟨a, b | abaaab=aaba⟩

Solved by morph:3/3,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaab ⇒ aaba
2. abaaaaba ⇒ aabaaaab
3. aaaabaaaabb ⇒ abaaaaaba
4. ababaaaaaba ⇒ aabaaaaabab
5. abaabaaaaaba ⇒ aabaaaaabaab
6. aabaaaabbaaab ⇒ aaabaaaabba
7. abaaaaabaaaab ⇒ aabaaaaabaa
8. aabaaaaababaab ⇒ ababaaaaaaba
9. aabaaaaabbaaab ⇒ aabaaaaababa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aaa, [3/1] aab, [3/2] aba, [3/3] baa
Length 4:[4/0] aaab, [4/1] abaa, [4/2] aaba, [4/3] aaaa
Length 5:[5/0] abaaa, [5/1] aaaab, [5/2] baaaa, [5/3] aabaa
Length 6:[6/0] abaaaa, [6/1] aaaaba, [6/2] aabaaa, [6/3] baaaab

Considering [length 3 / frequency 3] baa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. baa ⇒ c
2. acab ⇒ aaba
3. acac ⇒ aaca
4. ccab ⇒ caba
5. ccac ⇒ caca
6. acaaba ⇒ aacaab
7. acaaca ⇒ aacaac
8. cacaab ⇒ bacaac
9. ccaaba ⇒ bacaac
10. ccaaca ⇒ cacaac
11. aaacaab ⇒ acaac
12. abacaac ⇒ aacaaab
13. acaaaba ⇒ aacaacb
14. acaaaca ⇒ aacaacc
15. caacaab ⇒ ccaac
16. cacaacb ⇒ baccaac
17. cbacaac ⇒ cacaaab
18. ccaaaba ⇒ cacaacb
19. ccaaaca ⇒ cacaacc
20. aaacaacb ⇒ accaac
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ca, [2/1] ac, [2/2] aa, [2/3] ab, [2/4] cc, [2/5] ba, [2/6] cb
Length 3:[3/0] aca, [3/1] caa, [3/2] aac, [3/3] cca, [3/4] aba, [3/5] aab, [3/6] cac
Length 4:[4/0] acaa, [4/1] aaca, [4/2] caac, [4/3] ccaa, [4/4] caab, [4/5] aaba, [4/6] aaac
Length 5:[5/0] acaac, [5/1] acaab, [5/2] aaaca, [5/3] caaca, [5/4] ccaaa, [5/5] cacaa, [5/6] caacb

Considering [length 3 / frequency 0] aca=d.

Step 3

Rewriting system is complete. See ⟨a, b | abaaab=aaba⟩.