Morphocompletion for #2559 ⟨a, b | aabbba=bbaa⟩

Back:⟨a, b | aabbba=bbaa⟩

Solved by morph:4/3. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbba ⇒ bbaa
2. aabbbbbaa ⇒ bbabbaa
3. aabbbbbbbaa ⇒ bbabbbbaa
4. aabbbbbabbaa ⇒ bbabbabbaa
5. aabbbbbbbbbaa ⇒ bbabbbbbbaa
6. aabbbbbbbabbaa ⇒ bbabbbbabbaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] bb, [2/1] aa, [2/2] ba, [2/3] ab
Length 3:[3/0] bbb, [3/1] aab, [3/2] baa, [3/3] bba, [3/4] abb, [3/5] bab
Length 4:[4/0] bbbb, [4/1] aabb, [4/2] bbaa, [4/3] bbba, [4/4] abbb, [4/5] babb, [4/6] bbab
Length 5:[5/0] bbbbb, [5/1] aabbb, [5/2] bbbaa, [5/3] abbbb, [5/4] bbbba, [5/5] abbaa, [5/6] bbabb
Length 6:[6/0] aabbbb, [6/1] bbbbbb, [6/2] bbbbaa, [6/3] abbbbb, [6/4] bbbbba, [6/5] babbaa, [6/6] bbbabb
Length 7:[7/0] aabbbbb, [7/1] bbbbbaa, [7/2] bbbbbbb, [7/3] bbabbaa, [7/4] abbbbbb, [7/5] bbbbbba, [7/6] bbbbabb

Considering [length 4 / frequency 3] bbba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbba=bbaa⟩.