Morphocompletion for #2557 ⟨a, b | aabbba=baba⟩

Solved by morph:5/3. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: lhsLimit

#Rule
1. aabbba ⇒ baba
2. aabbbbaba ⇒ babbaba
3. aabbbbabbaba ⇒ babbabbaba
4. aabbbbabbabbaba ⇒ babbabbabbaba
5. aabbbbabbabbabbaba ⇒ babbabbabbabbaba
6. aabbbbabbabbabbabbaba ⇒ babbabbabbabbabbaba
7. aabbbbabbabbabbabbabbaba ⇒ babbabbabbabbabbabbaba
8. aabbbbabbabbabbabbabbabbaba ⇒ babbabbabbabbabbabbabbaba
9. aabbbbabbabbabbabbabbabbabbaba ⇒ babbabbabbabbabbabbabbabbaba
10. aabbbbabbabbabbabbabbabbabbabbaba ⇒ babbabbabbabbabbabbabbabbabbaba
11. aabbbbabbabbabbabbabbabbabbabbabbaba ⇒ babbabbabbabbabbabbabbabbabbabbaba
12. aabbbbabbabbabbabbabbabbabbabbabbabbaba ⇒ babbabbabbabbabbabbabbabbabbabbabbaba
13. aabbbbabbabbabbabbabbabbabbabbabbabbabbaba ⇒ babbabbabbabbabbabbabbabbabbabbabbabbaba
...

Collecting factors up to length 8 / frequency 7:

[2/0]bb104lf:104,rf:78
[2/1]ba104lf:91,ls:13,rf:104,rp:13,rs:13,lsrp:13,lsrs:13
[2/2]ab91lf:91,rf:91
[2/3]aa26lf:13,lp:13
[3/0]bba80lf:79,ls:1,rf:78
[3/1]abb79lf:79,rf:78
[3/2]bab78lf:78,rf:91,rp:13
[3/3]aab26lf:13,lp:13
[3/4]bbb25lf:25
[3/5]aba24lf:12,ls:12,rf:13,rs:13,lsrs:12
[4/0]bbab78lf:78,rf:78,a:1
[4/1]babb66lf:66,rf:78,rp:12,a:1
[4/2]abba66lf:66,rf:78,a:1
[4/3]aabb26lf:13,lp:13
[4/4]baba24lf:12,ls:12,rf:13,rp:1,rs:13,re:1,lsrs:12
[4/5]bbba14lf:13,ls:1
[4/6]abbb13lf:13
[5/0]bbabb66lf:66,rf:66,a:2
[5/1]babba66lf:66,rf:78,rp:12,a:1
[5/2]abbab66lf:66,rf:78,a:1
[5/3]aabbb26lf:13,lp:13
[5/4]bbaba24lf:12,ls:12,rf:12,rs:12,lsrs:12,a:1
[5/5]bbbba12lf:12,a:1
[5/6]bbbab12lf:12,a:1
[6/0]bbabba66lf:66,rf:66,a:2
[6/1]babbab66lf:66,rf:78,rp:12,a:1
[6/2]abbabb55lf:55,rf:66,a:2
[6/3]aabbbb24lf:12,lp:12,a:1
[6/4]abbaba22lf:11,ls:11,rf:12,rs:12,lsrs:11,a:1
[6/5]bbbbab12lf:12,a:1
[6/6]abbbba12lf:12,a:1
[7/0]bbabbab66lf:66,rf:66,a:2
[7/1]babbabb55lf:55,rf:66,rp:11,a:2
[7/2]abbabba55lf:55,rf:66,a:2
[7/3]aabbbba24lf:12,lp:12,a:1
[7/4]babbaba22lf:11,ls:11,rf:12,rp:1,rs:12,re:1,lsrs:11,a:1
[7/5]abbbbab12lf:12,a:1
[7/6]bbbbabb11lf:11,a:2

Considering [length 5 / frequency 3] aabbb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbba=baba⟩.