Morphocompletion for #2556 ⟨a, b | aabbba=baab⟩

Solved by morph:4/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aabbba ⇒ baab
2. baababbba ⇒ aabbbbaab
3. aabbaabbbbaab ⇒ baabababbba
4. baabababbbabba ⇒ aabbaabbbbbaab
5. baababbaabbbbaab ⇒ aabbbbaabababbba
6. aabbaabbaabbbbbaab ⇒ baababababbbabba
7. baababababbbabbabba ⇒ aabbaabbaabbbbbbaab
8. baabababbbabaabbbbaab ⇒ aabbaabbbbbaabababbba
9. baababbaabbaabbbbbaab ⇒ aabbbbaababababbbabba
10. aabbaabbaabbaabbbbbbaab ⇒ baabababababbbabbabba
11. aabbaabbbbaaaabbbbaab ⇒ baabababbbaaababbba
...

Collecting factors up to length 8 / frequency 7:

[2/0]ba53lf:43,lp:6,ls:4,rf:46,rp:5,rs:7,lsrp:1,lprs:3
[2/1]ab51lf:44,ls:7,rf:45,rs:4
[2/2]bb51lf:51,rf:46
[2/3]aa37lf:32,lp:5,rf:23,rp:6
[3/0]aab42lf:30,lp:5,ls:7,rf:22,rp:6,rs:4,lsrp:3,lprs:1
[3/1]baa31lf:25,lp:6,rf:16,rp:5
[3/2]bba30lf:26,ls:4,rf:22,rs:7
[3/3]abb26lf:26,rf:22
[3/4]bbb25lf:25,rf:24
[3/5]bab14lf:14,rf:23,a:1
[3/6]aba11lf:11,rf:19,a:1
[4/0]baab37lf:24,lp:6,ls:7,rf:15,rp:5,rs:4,re:1,lsrp:4,lprs:3
[4/1]aabb22lf:17,lp:5,rf:10,rp:6
[4/2]bbaa18lf:18,rf:11,a:1
[4/3]abba15lf:13,ls:2,rf:8,rs:3,a:2
[4/4]bbba15lf:13,ls:2,rf:14,rs:4
[4/5]abbb13lf:13,rf:14
[4/6]bbbb12lf:12,rf:10,a:1
[5/0]bbaab24lf:17,ls:7,rf:10,rs:3,a:1
[5/1]baaba12lf:6,lp:6,rf:7,rp:4,a:1
[5/2]aabba12lf:8,lp:4,rf:4,rp:3,a:2
[5/3]baabb11lf:11,rf:4,a:2
[5/4]abbaa10lf:10,rf:4,a:2
[5/5]aabbb10lf:9,lp:1,rf:6,rp:3
[5/6]bbbaa8lf:8,rf:7,a:1
[6/0]bbbaab14lf:7,ls:7,rf:6,rs:3,a:1
[6/1]aabbaa12lf:8,lp:4,rf:4,rp:3,a:2
[6/2]baabab12lf:6,lp:6,rf:7,rp:4,a:1
[6/3]abbaab10lf:10,rf:4,a:2
[6/4]bbaabb10lf:10,rf:4,a:2
[6/5]bbbbaa8lf:8,rf:6,a:1
[6/6]aabbbb8lf:8,rf:6,rp:3,a:1
[7/0]bbbbaab14lf:7,ls:7,rf:6,rs:3,a:1
[7/1]aabbaab12lf:8,lp:4,rf:4,rp:3,a:2
[7/2]abbaabb10lf:10,rf:4,a:2
[7/3]baabbbb7lf:7,rf:3,a:2
[7/4]baababa6lf:3,lp:3,rf:7,rp:4,a:2
[7/5]baababb6lf:3,lp:3,a:1
[7/6]bbaabbb6lf:6,rf:3,a:2

Considering [length 4 / frequency 1] aabb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbba=baab⟩.