Morphocompletion for #2556 ⟨a, b | aabbba=baab

Solved by morph:4/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. aabbba ⇒ baab
2. baababbba ⇒ aabbbbaab
3. aabbaabbbbaab ⇒ baabababbba
4. baabababbbabba ⇒ aabbaabbbbbaab
5. baababbaabbbbaab ⇒ aabbbbaabababbba
6. aabbaabbaabbbbbaab ⇒ baababababbbabba
7. baababababbbabbabba ⇒ aabbaabbaabbbbbbaab
8. baabababbbabaabbbbaab ⇒ aabbaabbbbbaabababbba
9. baababbaabbaabbbbbaab ⇒ aabbbbaababababbbabba
10. aabbaabbbbaaaabbbbaab ⇒ baabababbbaaababbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] ab, [2/2] bb, [2/3] aa
Length 3:[3/0] aab, [3/1] baa, [3/2] bba, [3/3] abb, [3/4] bbb, [3/5] bab, [3/6] aba
Length 4:[4/0] baab, [4/1] aabb, [4/2] bbaa, [4/3] bbba, [4/4] abba, [4/5] abbb, [4/6] abab
Length 5:[5/0] bbaab, [5/1] baaba, [5/2] aabbb, [5/3] aabba, [5/4] baabb, [5/5] abbaa, [5/6] bbbaa
Length 6:[6/0] baabab, [6/1] bbbaab, [6/2] aabbaa, [6/3] abbaab, [6/4] bbbbaa, [6/5] bbaabb, [6/6] aabbbb
Length 7:[7/0] bbbbaab, [7/1] aabbaab, [7/2] abbaabb, [7/3] baababa, [7/4] baababb, [7/5] baabbbb, [7/6] abbbbaa

Considering [length 4 / frequency 1] aabb=c.

Step 2

Rewriting system is complete. See a, b | aabbba=baab.