Morphocompletion for #2528 ⟨a, b | aabbaa=baab⟩

Solved by morph:5/1,2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbaa ⇒ baab
2. aabbbaab ⇒ baabbbaa
3. aabbabaab ⇒ baababbaa
4. aabbbbaab ⇒ bbaabbbaaaa
5. aabbabbaab ⇒ baababbaabaa
6. aabbbbbaab ⇒ bbaabbbaaaabaa
7. aabbabbbaab ⇒ baababbaabaabaa
8. aabbbbbbaab ⇒ bbaabbbaaaabaabaa
9. aabbabbbbaab ⇒ baababbaabaabaabaa
10. aabbbbbbbaab ⇒ bbaabbbaaaabaabaabaa
11. aabbabbbbbaab ⇒ baababbaabaabaabaabaa
12. aabbbbbbbbaab ⇒ bbaabbbaaaabaabaabaabaa
13. aabbabbbbbbaab ⇒ baababbaabaabaabaabaabaa
14. aabbbbbbbbbaab ⇒ bbaabbbaaaabaabaabaabaabaa
15. aabbabbbbbbbaab ⇒ baababbaabaabaabaabaabaabaa
16. aabbbbbbbbbbaab ⇒ bbaabbbaaaabaabaabaabaabaabaa
17. aabbabbbbbbbbaab ⇒ baababbaabaabaabaabaabaabaabaa
18. aabbabbbbbbbbbaabbbaaaa ⇒ baababbbaabbbbbbbbbaa
19. aabbbbbbbbbbbbaabbbaaaa ⇒ bbbaabbbaaaabbbbbbbbbaa
...

Collecting factors up to length 7 / frequency 4:

[2/0]bb105lf:105,rf:53,rp:8
[2/1]aa66lf:44,lp:19,ls:3,rf:104,rs:18,lprs:18,lsrs:2
[2/2]ab62lf:46,ls:16,rf:79,rs:1
[2/3]ba30lf:30,rf:97,rp:11
[3/0]bbb76lf:76,rf:25,rp:1,a:1
[3/1]aab72lf:37,lp:19,ls:16,rf:70,rs:1,lprs:1
[3/2]abb29lf:29,rf:20
[3/3]bba29lf:29,rf:28,rp:7
[4/0]bbbb58lf:58,rf:12,a:4
[4/1]aabb40lf:21,lp:19,rf:11
[4/2]baab34lf:18,ls:16,rf:63,rp:11,rs:1,re:1,lsrp:9
[4/3]bbaa21lf:20,ls:1,rf:28,rp:7,rs:4
[5/0]bbbbb44lf:44,rf:10,a:9
[5/1]bbaab32lf:17,ls:15,rf:16,rp:7,lsrp:7,a:1
[5/2]aabbb20lf:11,lp:9,rf:11,a:1
[5/3]aabba20lf:10,lp:10
[6/0]bbbbbb32lf:32,rf:8,a:14
[6/1]bbbaab30lf:16,ls:14,rf:2,rp:1,a:1
[6/2]aabbab18lf:9,lp:9,a:2
[6/3]aabbbb16lf:8,lp:8,rf:2,a:4

Considering [length 5 / frequency 1] bbaab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aacaa ⇒ c
2. aacc ⇒ ccaa
3. aacac ⇒ cacaa
4. bc ⇒ cbaa
5. baac ⇒ cb
6. aabbaa ⇒ baab
7. aacbaab ⇒ cbbaa
8. aacabaab ⇒ cabbaa
9. bbaaaac ⇒ caabb
10. aabbac ⇒ baabacaa
11. bbaab ⇒ c
12. baabb ⇒ aac
13. aabbabaab ⇒ baababbaa
14. cbbaaaabb ⇒ aacbaaaac
15. cabbaaaabb ⇒ aacabaaaac
16. cbbbaaaabb ⇒ baaaacbaaaac
17. cbabbaaaabb ⇒ baaaacabaaaac
18. baababbaaaabb ⇒ aabbabaaaac
19. cbbbbaaaabb ⇒ baabaaaacbaaaac
...

Collecting factors up to length 6 / frequency 7:

[2/0]aa48lf:38,lp:8,ls:2,rf:43,rp:4,rs:7,lprs:6
[2/1]bb30lf:21,lp:2,ls:7,rf:5,rs:1,lprs:1
[2/2]ab24lf:20,ls:4,rf:11,rs:1
[2/3]ba22lf:19,lp:3,rf:20,rp:6
[2/4]ac13lf:9,ls:4,rf:14,rs:7,a:4
[2/5]cb9lf:5,lp:4,rf:6,rp:3,rs:1,re:1,a:5
[2/6]ca5lf:4,lp:1,rf:8,rp:3,a:12
[3/0]aab22lf:15,lp:3,ls:4,rf:6,rp:1,rs:1,lprs:1
[3/1]abb20lf:13,ls:7,rf:4,rs:1
[3/2]baa19lf:15,lp:3,ls:1,rf:17,rp:6,rs:4,lsrp:1
[3/3]aac14lf:7,lp:5,ls:2,rf:12,rp:3,rs:7,re:1,a:4
[3/4]aaa14lf:14,rf:18,a:12
[3/5]bba13lf:11,lp:2,rf:4
[3/6]cbb6lf:3,lp:3,rf:1,rp:1,a:14
[4/0]aabb20lf:10,lp:3,ls:7,rf:2,rp:1,rs:1,lsrp:1
[4/1]baab12lf:6,lp:2,ls:4,rf:4,rp:4,rs:1,re:1,lsrp:1
[4/2]bbaa12lf:9,lp:2,ls:1,rf:3,rs:3
[4/3]baaa7lf:7,rf:9,rp:2,a:12
[4/4]aaaa7lf:7,rf:9,a:12
[4/5]abba6lf:6,rf:3
[4/6]aaab6lf:6,a:20
[5/0]aaabb12lf:6,ls:6,a:20
[5/1]bbaaa8lf:7,lp:1,a:12
[5/2]baaaa7lf:7,rf:9,rp:2,a:12
[5/3]aabba6lf:3,lp:3,rf:1,rp:1
[5/4]aaaab6lf:6,a:20
[5/5]abbaa5lf:4,ls:1,rf:2,rs:2
[5/6]abaab4lf:2,ls:2,a:3

Considering [length 2 / frequency 1] bb=d.

Step 3

Rewriting system is complete. See ⟨a, b | aabbaa=baab⟩.