| Back: | ⟨a, b | aabaab=baaa⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabbaaa ⇒ baaaaab |
| 2. | aabaab ⇒ baaa |
| 3. | baaaaabbaab ⇒ aabbabaaa |
| 4. | baaaaababaab ⇒ aabbaabaaa |
| 5. | aabbabaaaaab ⇒ baaaaabbbaaa |
| 6. | aabbaabaaaaab ⇒ baaaaababbaaa |
| 7. | aabaaaabbabaaa ⇒ baaaaaaaabbaab |
| 8. | aabaaaabbaabaaa ⇒ baaaaaaaababaab |
| 9. | baaaaabbbaaaaab ⇒ aabbabaaabaaa |
| 10. | baaaaababbaaaaab ⇒ aabbaabaaabaaa |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 64 | lf:55,lp:6,ls:3,rf:52,rp:4,rs:7,lprs:3 |
|---|---|---|---|
| [2/1] | ab | 32 | lf:25,ls:7,rf:19,rs:3 |
| [2/2] | ba | 26 | lf:22,lp:4,rf:22,rp:6 |
| [2/3] | bb | 9 | lf:9,rf:8,a:1 |
| [3/0] | aab | 34 | lf:21,lp:6,ls:7,rf:15,rp:4,rs:3,lsrp:4,lprs:3 |
| [3/1] | aaa | 34 | lf:31,ls:3,rf:30,rs:7 |
| [3/2] | baa | 22 | lf:18,lp:4,rf:18,rp:6 |
| [3/3] | aba | 10 | lf:10,rf:9 |
| [3/4] | abb | 8 | lf:8,rf:7,a:1 |
| [3/5] | bba | 8 | lf:8,rf:7,a:1 |
| [3/6] | bab | 4 | lf:4,rf:4,a:2 |
| [4/0] | baaa | 20 | lf:13,lp:4,ls:3,rf:14,rp:6,rs:7,re:1,lsrp:3,lprs:4 |
| [4/1] | aaaa | 18 | lf:18,rf:16,a:1 |
| [4/2] | aaab | 14 | lf:10,ls:4,rf:7,rs:1,a:1 |
| [4/3] | aabb | 10 | lf:7,lp:3,rf:6,rp:4,a:1 |
| [4/4] | aaba | 10 | lf:7,lp:3,rf:6 |
| [4/5] | baab | 8 | lf:5,ls:3,rf:4,rs:2 |
| [4/6] | abaa | 8 | lf:8,rf:7 |
| [5/0] | aaaab | 14 | lf:10,ls:4,rf:5,rs:1,a:1 |
| [5/1] | baaaa | 14 | lf:10,lp:4,rf:5,rp:5,a:1 |
| [5/2] | aabba | 9 | lf:6,lp:3,rf:5,rp:4,a:1 |
| [5/3] | aabaa | 8 | lf:5,lp:3,rf:4 |
| [5/4] | abaaa | 8 | lf:6,ls:2,rf:6,rs:4,a:2 |
| [5/5] | aaaaa | 8 | lf:8,rf:11,a:1 |
| [5/6] | abbaa | 5 | lf:5,rf:4,a:1 |
| [6/0] | aaaaab | 12 | lf:8,ls:4,rf:5,rs:1,a:1 |
| [6/1] | baaaaa | 12 | lf:8,lp:4,rf:5,rp:5,a:1 |
| [6/2] | aabaaa | 7 | lf:4,lp:2,ls:1,rf:4,rs:3,a:3 |
| [6/3] | aabbaa | 6 | lf:4,lp:2,rf:3,rp:2,a:1 |
| [6/4] | abbaab | 4 | lf:3,ls:1,rf:3,rs:1,a:2 |
| [6/5] | aaaabb | 4 | lf:4,rf:2,a:2 |
| [6/6] | abaaaa | 4 | lf:4,a:4 |
| [7/0] | baaaaab | 16 | lf:8,lp:4,ls:4,rf:3,rp:3,rs:1,re:1,lsrp:2,a:1 |
| [7/1] | aabbaab | 5 | lf:3,lp:1,ls:1,rf:3,rp:2,rs:1,a:2 |
| [7/2] | aabaaaa | 5 | lf:3,lp:2,a:5 |
| [7/3] | aabbaba | 3 | lf:2,lp:1,rf:2,rp:2,a:2 |
| [7/4] | bbabaaa | 3 | lf:2,ls:1,rf:2,rs:1,a:2 |
| [7/5] | aaaabba | 3 | lf:3,rf:1,a:2 |
| [7/6] | baabaaa | 3 | lf:2,ls:1,rf:2,rs:1,a:3 |
Considering [length 3 / frequency 0] aab=c.
Rewriting system is complete. See ⟨a, b | aabaab=baaa⟩.