| Back: | ⟨a, b | aabaab=abaa⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabaab ⇒ abaa |
| 2. | aababaa ⇒ abaaaab |
| 3. | abaaaabbaab ⇒ aabababaa |
| 4. | abaaabaaaabb ⇒ abaaaabbaa |
| 5. | aabababaaaab ⇒ abaaaabbabaa |
| 6. | abaaaabababaa ⇒ abaaaabbaaaab |
| 7. | aabaaabababaa ⇒ abaaaaaabbaab |
| 8. | abaaaaabaaaabb ⇒ abaaaaaabbaa |
| 9. | abaaaabbabaaaab ⇒ aabababaaabaa |
| 10. | abaaaaaabababaa ⇒ abaaaaaabbaaaab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 52 | lf:44,lp:4,ls:4,rf:44,rp:2,rs:6,lprs:2 |
|---|---|---|---|
| [2/1] | ab | 43 | lf:33,lp:6,ls:4,rf:26,rp:8,rs:4,lprp:4,lsrp:2,lprs:2 |
| [2/2] | ba | 27 | lf:27,rf:22 |
| [2/3] | bb | 6 | lf:4,ls:2,rf:6,a:2 |
| [3/0] | aba | 31 | lf:25,lp:6,rf:16,rp:8,lprp:4 |
| [3/1] | aab | 25 | lf:17,lp:4,ls:4,rf:13,rp:2,rs:4,lsrp:2,lprs:2 |
| [3/2] | aaa | 23 | lf:23,rf:25,a:1 |
| [3/3] | baa | 21 | lf:17,ls:4,rf:17,rs:6 |
| [3/4] | bab | 10 | lf:10,rf:5,a:1 |
| [3/5] | abb | 6 | lf:4,ls:2,rf:6,a:2 |
| [3/6] | bba | 2 | lf:2,rf:6,a:2 |
| [4/0] | abaa | 26 | lf:16,lp:6,ls:4,rf:12,rp:8,rs:4,re:1,lprp:4,lsrp:4,lprs:2 |
| [4/1] | aaab | 13 | lf:11,ls:2,rf:10,rs:3,a:1 |
| [4/2] | aaba | 13 | lf:9,lp:4,rf:3,rp:2 |
| [4/3] | aaaa | 12 | lf:12,rf:15,a:1 |
| [4/4] | baaa | 11 | lf:11,rf:10,a:1 |
| [4/5] | baba | 10 | lf:10,rf:5,a:1 |
| [4/6] | abab | 9 | lf:9,rf:4,a:1 |
| [5/0] | abaaa | 17 | lf:11,lp:6,rf:8,rp:7,lprp:4,a:1 |
| [5/1] | aaaab | 11 | lf:9,ls:2,rf:9,rs:3,a:1 |
| [5/2] | babaa | 10 | lf:6,ls:4,rf:3,rs:2,a:1 |
| [5/3] | ababa | 9 | lf:9,rf:4,a:1 |
| [5/4] | baaaa | 9 | lf:9,rf:9,a:1 |
| [5/5] | aabab | 7 | lf:5,lp:2,rf:2,rp:2,a:1 |
| [5/6] | aaabb | 6 | lf:4,ls:2,rf:6,a:2 |
| [6/0] | abaaaa | 14 | lf:9,lp:5,rf:7,rp:7,lprp:3,a:1 |
| [6/1] | ababaa | 9 | lf:5,ls:4,rf:2,rs:1,a:1 |
| [6/2] | baaaab | 9 | lf:7,ls:2,rf:6,rs:3,a:1 |
| [6/3] | aababa | 7 | lf:5,lp:2,rf:2,rp:2,a:1 |
| [6/4] | aaaabb | 6 | lf:4,ls:2,rf:6,a:2 |
| [6/5] | aabaaa | 4 | lf:3,lp:1,a:3 |
| [6/6] | ababab | 4 | lf:4,rf:2,a:2 |
| [7/0] | abaaaab | 12 | lf:7,lp:3,ls:2,rf:4,rp:4,rs:1,re:1,lprp:1,lsrp:1,a:1 |
| [7/1] | bababaa | 7 | lf:4,ls:3,rf:2,rs:1,a:2 |
| [7/2] | baaaabb | 6 | lf:4,ls:2,rf:3,a:2 |
| [7/3] | aababab | 5 | lf:4,lp:1,rf:2,rp:2,a:2 |
| [7/4] | abaaaaa | 4 | lf:2,lp:2,rf:3,rp:3,lprp:2,a:6 |
| [7/5] | abababa | 4 | lf:4,rf:2,a:2 |
| [7/6] | aaababa | 3 | lf:3,a:5 |
Considering [length 3 / frequency 0] aba=c.
Rewriting system is complete. See ⟨a, b | aabaab=abaa⟩.