Morphocompletion for #2426 ⟨a, b | aaabaa=abab⟩

Solved by morph:2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#	Rule
1.	abab ⇒ aaabaa
2.	aaabaaab ⇒ abaaabaa
3.	abaaabaaaaab ⇒ aaaaabaaaaabaa
4.	abaaabaaaaaaab ⇒ aaaaaaabaaaaabaa
5.	abaaabaaaaaaaaab ⇒ aaaaaaaaabaaaaabaa
6.	abaaabaaaaaaaaaaab ⇒ aaaaaaaaaaabaaaaabaa
7.	abaaabaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaabaaaaabaa
8.	abaaabaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaabaaaaabaa
9.	abaaabaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaabaaaaabaa
10.	abaaabaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaabaaaaabaa
11.	abaaabaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaaabaaaaabaa
12.	abaaabaaaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaaaaabaaaaabaa
13.	aaabaaaaabaaaaab ⇒ abaaaaabaaaaabaa
14.	aaabaaaaabaaaaaaab ⇒ abaaaaaaabaaaaabaa
15.	aaabaaaaabaaaaaaaaab ⇒ abaaaaaaaaabaaaaabaa
16.	aaabaaaaabaaaaaaaaaaab ⇒ abaaaaaaaaaaabaaaaabaa
17.	aaabaaaaabaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaabaaaaabaa
18.	aaabaaaaabaaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaaaabaaaaabaa
19.	aaabaaaaabaaaaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaaaaaabaaaaabaa
20.	aaabaaaaabaaaaaaaaaaaaaaaaaaab ⇒ abaaaaaaaaaaaaaaaaaaabaaaaabaa
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] aa, [2/1] ab, [2/2] ba
Length 3:	[3/0] aaa, [3/1] aab, [3/2] aba, [3/3] baa, [3/4] bab
Length 4:	[4/0] aaaa, [4/1] aaab, [4/2] abaa, [4/3] baaa, [4/4] aaba
Length 5:	[5/0] aaaaa, [5/1] abaaa, [5/2] aaaab, [5/3] aaaba, [5/4] aabaa, [5/5] baaaa, [5/6] baaab
Length 6:	[6/0] aaaaaa, [6/1] aaaaab, [6/2] aaabaa, [6/3] aabaaa, [6/4] abaaaa, [6/5] baaaaa, [6/6] abaaab
Length 7:	[7/0] aaaaaaa, [7/1] aaabaaa, [7/2] aaaaaab, [7/3] aabaaaa, [7/4] abaaaaa, [7/5] abaaaba, [7/6] baaaaaa

Considering [length 2 / frequency 1] ab=c.

Auxiliary generators:
1. c = ab
Reduction order:
- Left-to-right recursive path with deg(a) = deg(c) = 0, a < c; deg(b) = 1

Rewriting system is complete. See ⟨a, b | aaabaa=abab⟩.