| Back: | ⟨a, b | ababaab=bab⟩ |
|---|
Solved by morph:2/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | ababaab ⇒ bab |
| 2. | bbabab ⇒ abbbab |
| 3. | abababab ⇒ bbab |
| 4. | bbabaab ⇒ ababbab |
| 5. | bbabbab ⇒ abbbbab |
| 6. | abababbab ⇒ bbbab |
| 7. | bbabbbab ⇒ abbbbbab |
| 8. | abababbbab ⇒ bbbbab |
| 9. | bbaabbbab ⇒ aabbbbbab |
| 10. | ababaaabbbab ⇒ baabbbab |
| 11. | bbaababbab ⇒ aababbbbab |
| 12. | bbabbbbab ⇒ abbbbbbab |
| 13. | abababbbbab ⇒ bbbbbab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | ab | 57 | lf:38,lp:6,ls:13,rf:23,rp:5,rs:13,lsrp:5,lprs:6,lsrs:13 |
|---|---|---|---|
| [2/1] | ba | 32 | lf:32,rf:16,rp:2 |
| [2/2] | bb | 31 | lf:24,lp:7,rf:34,rp:4,a:1 |
| [2/3] | aa | 6 | lf:6,rf:3,rp:2 |
| [3/0] | bab | 38 | lf:27,ls:11,rf:15,rp:1,rs:13,re:1,lsrs:11 |
| [3/1] | bba | 23 | lf:16,lp:7,rf:12,rp:1,a:1 |
| [3/2] | aba | 22 | lf:16,lp:6,rf:2,rp:1 |
| [3/3] | abb | 9 | lf:9,rf:8,rp:4,a:2 |
| [3/4] | bbb | 8 | lf:8,rf:22,rp:3,a:2 |
| [3/5] | aab | 7 | lf:5,ls:2,rf:3,rp:2 |
| [3/6] | baa | 5 | lf:5,rf:1,rp:1 |
| [4/0] | bbab | 28 | lf:14,lp:5,ls:9,rf:12,rp:1,rs:12,re:1,lprs:5,lsrs:9,a:1 |
| [4/1] | abab | 21 | lf:13,lp:6,ls:2,rf:2,rp:1 |
| [4/2] | baba | 9 | lf:9 |
| [4/3] | babb | 7 | lf:7,rf:2,a:2 |
| [4/4] | bbba | 6 | lf:6,rf:10,rp:1,a:2 |
| [4/5] | abbb | 6 | lf:6,rf:7,rp:4,a:4 |
| [4/6] | baab | 6 | lf:4,ls:2,rf:1,rp:1 |
| [5/0] | ababa | 13 | lf:7,lp:6 |
| [5/1] | bbbab | 12 | lf:6,ls:6,rf:10,rp:1,rs:10,re:1,lsrs:6,a:2 |
| [5/2] | babab | 8 | lf:6,ls:2,a:1 |
| [5/3] | bbabb | 6 | lf:3,lp:3,a:13 |
| [5/4] | abbab | 6 | lf:3,ls:3,rf:1,rs:1,a:2 |
| [5/5] | babbb | 4 | lf:4,rf:1,a:7 |
| [5/6] | bbaba | 4 | lf:2,lp:2,a:3 |
| [6/0] | ababab | 10 | lf:5,lp:4,ls:1,a:1 |
| [6/1] | abbbab | 8 | lf:4,ls:4,rf:2,rp:1,rs:2,re:1,lsrs:1,a:4 |
| [6/2] | babbab | 6 | lf:3,ls:3,rf:1,rs:1,a:2 |
| [6/3] | bbbbab | 4 | lf:2,ls:2,rf:7,rp:1,rs:7,re:1,lsrs:2,a:6 |
| [6/4] | bbabbb | 4 | lf:2,lp:2,a:19 |
| [6/5] | babaab | 4 | lf:2,ls:2 |
| [6/6] | ababaa | 4 | lf:2,lp:2 |
| [7/0] | abababb | 6 | lf:3,lp:3,a:2 |
| [7/1] | babbbab | 4 | lf:2,ls:2,a:7 |
| [7/2] | abbbbab | 4 | lf:2,ls:2,rf:2,rp:1,rs:2,re:1,a:9 |
| [7/3] | ababbab | 4 | lf:2,ls:2,rf:1,rp:1,rs:1,re:1,a:2 |
| [7/4] | aabbbab | 4 | lf:2,ls:2,rf:1,rs:1,lsrs:1,a:5 |
| [7/5] | bbabbbb | 2 | lf:1,lp:1,a:35 |
| [7/6] | bbabbba | 2 | lf:1,lp:1,a:19 |
Considering [length 2 / frequency 0] ab=c.
Rewriting system is complete. See ⟨a, b | ababaab=bab⟩.