| Back: | ⟨a, b | ababaab=aab⟩ |
|---|
Solved by morph:5/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | ababaab ⇒ aab |
| 2. | ababaaab ⇒ aaab |
| 3. | ababaaaab ⇒ aaaab |
| 4. | ababaaaaab ⇒ aaaaab |
| 5. | ababaaaaaab ⇒ aaaaaab |
| 6. | ababaaaaaaab ⇒ aaaaaaab |
| 7. | ababaaaaaaaab ⇒ aaaaaaaab |
| 8. | ababaaaaaaaaab ⇒ aaaaaaaaab |
| 9. | ababaaaaaaaaaab ⇒ aaaaaaaaaab |
| 10. | ababaaaaaaaaaaab ⇒ aaaaaaaaaaab |
| 11. | ababaaaaaaaaaaaab ⇒ aaaaaaaaaaaab |
| 12. | ababaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaab |
| 13. | ababaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaab |
| 14. | ababaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaab |
| 15. | ababaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaab |
| 16. | ababaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaab |
| 17. | ababaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaab |
| 18. | ababaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaab |
| 19. | ababaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaab |
| 20. | ababaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaaab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 210 | lf:210,rf:210,rp:20 |
|---|---|---|---|
| [2/1] | ab | 100 | lf:60,lp:20,ls:20,rf:20,rs:20,lprs:20,lsrs:20 |
| [2/2] | ba | 40 | lf:40 |
| [3/0] | aaa | 190 | lf:190,rf:190,rp:19,a:1 |
| [3/1] | aba | 60 | lf:40,lp:20 |
| [3/2] | aab | 40 | lf:20,ls:20,rf:20,rp:1,rs:20,re:1,lsrp:1,lsrs:20 |
| [3/3] | bab | 20 | lf:20 |
| [3/4] | baa | 20 | lf:20 |
| [4/0] | aaaa | 171 | lf:171,rf:171,rp:18,a:2 |
| [4/1] | abab | 40 | lf:20,lp:20 |
| [4/2] | aaab | 38 | lf:19,ls:19,rf:19,rp:1,rs:19,re:1,lsrp:1,lsrs:19,a:1 |
| [4/3] | baba | 20 | lf:20 |
| [4/4] | abaa | 20 | lf:20 |
| [4/5] | baaa | 19 | lf:19,a:1 |
| [4/6] | baab | 2 | lf:1,ls:1 |
| [5/0] | aaaaa | 153 | lf:153,rf:153,rp:17,a:3 |
| [5/1] | ababa | 40 | lf:20,lp:20 |
| [5/2] | aaaab | 36 | lf:18,ls:18,rf:18,rp:1,rs:18,re:1,lsrp:1,lsrs:18,a:2 |
| [5/3] | babaa | 20 | lf:20 |
| [5/4] | abaaa | 19 | lf:19,a:1 |
| [5/5] | baaaa | 18 | lf:18,a:2 |
| [5/6] | baaab | 2 | lf:1,ls:1,a:1 |
| [6/0] | aaaaaa | 136 | lf:136,rf:136,rp:16,a:4 |
| [6/1] | ababaa | 40 | lf:20,lp:20 |
| [6/2] | aaaaab | 34 | lf:17,ls:17,rf:17,rp:1,rs:17,re:1,lsrp:1,lsrs:17,a:3 |
| [6/3] | babaaa | 19 | lf:19,a:1 |
| [6/4] | abaaaa | 18 | lf:18,a:2 |
| [6/5] | baaaaa | 17 | lf:17,a:3 |
| [6/6] | babaab | 2 | lf:1,ls:1 |
| [7/0] | aaaaaaa | 120 | lf:120,rf:120,rp:15,a:5 |
| [7/1] | ababaaa | 38 | lf:19,lp:19,a:1 |
| [7/2] | aaaaaab | 32 | lf:16,ls:16,rf:16,rp:1,rs:16,re:1,lsrp:1,lsrs:16,a:4 |
| [7/3] | babaaaa | 18 | lf:18,a:2 |
| [7/4] | abaaaaa | 17 | lf:17,a:3 |
| [7/5] | baaaaaa | 16 | lf:16,a:4 |
| [7/6] | babaaab | 2 | lf:1,ls:1,a:1 |
Considering [length 5 / frequency 1] ababa=c.
Rewriting system is complete. See ⟨a, b | ababaab=aab⟩.