Morphocompletion for #2317 ⟨a, b | abaabba=baa⟩

Solved by morph:5/1,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaabba ⇒ baa
2. abaabbbaa ⇒ babaa
3. abaabbbbaa ⇒ babbaa
4. abaabbbabaa ⇒ bababaa
5. abaabbbbbaa ⇒ babbbaa
6. abaabbbbabaa ⇒ babbabaa
7. abaabbbabbaa ⇒ bababbaa
8. abaabbbababaa ⇒ babababaa
...

Collecting factors up to length 7 / frequency 4:

[2/0]ab29lf:21,lp:8,rf:12
[2/1]ba22lf:21,ls:1,rf:20,rp:8,lsrp:1
[2/2]aa22lf:15,ls:7,rf:8,rs:8,lsrs:7
[2/3]bb20lf:20,rf:5
[3/0]baa22lf:15,ls:7,rf:8,rp:1,rs:8,re:1,lsrs:7
[3/1]aba20lf:12,lp:8,rf:8
[3/2]bbb11lf:11,rf:1,a:1
[3/3]bba10lf:9,ls:1,rf:4
[4/0]abaa22lf:11,lp:8,ls:3,rf:4,rs:4,lprs:4,lsrs:3
[4/1]aabb8lf:8
[4/2]baab8lf:8
[4/3]bbaa8lf:4,ls:4,rf:3,rs:3,lsrs:3,a:1
[5/0]abaab16lf:8,lp:8
[5/1]baabb8lf:8
[5/2]aabbb7lf:7,a:1
[5/3]bbbaa6lf:3,ls:3,rf:1,rs:1,lsrs:1,a:1
[6/0]abaabb16lf:8,lp:8
[6/1]baabbb7lf:7,a:1
[6/2]bbbbaa4lf:2,ls:2,a:5
[6/3]aabbba4lf:4,a:1

Considering [length 5 / frequency 1] baabb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. baa ⇒ aca
2. bac ⇒ acc
3. acaacca ⇒ caa
4. acabcaa ⇒ caaacca
5. caabb ⇒ acabc
6. acabb ⇒ c
7. babc ⇒ acbc
8. accaacca ⇒ bcaa
9. acaaccc ⇒ cac
10. accabb ⇒ bc
11. acabcac ⇒ caaaccc
12. babbc ⇒ acbbc
13. acccaacca ⇒ bbcaa
14. accaaccc ⇒ bcac
15. acaaccbc ⇒ cabc
16. acccabb ⇒ bbc
17. babbbc ⇒ acbbbc
18. acccaaccc ⇒ bbcac
19. accaaccbc ⇒ bcabc
20. accccabb ⇒ bbbc
...

Collecting factors up to length 6 / frequency 7:

[2/0]ac40lf:24,lp:14,ls:2,rf:11,rp:6,rs:3,lsrp:10,lprs:3,a:2
[2/1]cc27lf:24,ls:3,rf:4,rs:2,a:4
[2/2]ca24lf:20,lp:1,ls:3,rf:13,rp:5,rs:2,lsrp:1,a:2
[2/3]bb13lf:8,ls:5,rf:8,rp:4,lsrp:2,a:3
[2/4]aa13lf:11,ls:2,rf:7,rs:3,a:2
[2/5]bc12lf:7,ls:5,rf:14,rp:4,rs:9,re:1,lsrp:1,lsrs:5,a:7
[2/6]ab10lf:10,rf:3,a:3
[3/0]acc24lf:16,lp:8,rf:3,rp:1,rs:1,re:1,a:4
[3/1]cca14lf:11,ls:3,rf:1,rs:1,a:5
[3/2]abb12lf:7,ls:5,a:3
[3/3]aca12lf:6,lp:6,rf:2,rp:2,rs:1,re:1,a:2
[3/4]caa12lf:10,lp:1,ls:1,rf:5,rp:3,rs:3,re:1,lsrp:1,a:5
[3/5]ccc11lf:8,ls:3,rf:1,rs:1,a:6
[3/6]aac8lf:8,rf:2,a:5
[4/0]accc14lf:7,lp:4,ls:3,rf:1,rs:1,a:6
[4/1]acca14lf:7,lp:4,ls:3,rf:1,rs:1,a:5
[4/2]cabb8lf:4,ls:4,a:3
[4/3]aacc8lf:8,rf:2,a:5
[4/4]caac8lf:8,a:5
[4/5]acab6lf:3,lp:3,rf:1,rp:1,a:3
[4/6]acaa6lf:3,lp:3,a:5
[5/0]caacc8lf:8,a:5
[5/1]ccabb6lf:3,ls:3,a:7
[5/2]aaccc6lf:3,ls:3,rf:1,rs:1,a:6
[5/3]accca6lf:3,lp:3,a:9
[5/4]aacca6lf:3,ls:3,rf:1,rs:1,a:5
[5/5]acaac6lf:3,lp:3,a:5
[5/6]accaa6lf:3,lp:3,a:10

Considering [length 3 / frequency 0] acc=d.

Step 3

Rewriting system is complete. See ⟨a, b | abaabba=baa⟩.