Morphocompletion for #2311 ⟨a, b | abaabab=bba

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. abaabab ⇒ bba
2. abaabbba ⇒ bbaaabab
3. bbaaababbaabab ⇒ abaabbbbba
4. abaabaabaabbbbba ⇒ bbabaaababbaabab
5. bbaaababbaabbba ⇒ abaabbbbbaaabab
6. bbabaaababbaababbaabab ⇒ abaabaabaabbbbbbba
7. abaabaabaabaabaabbbbbbba ⇒ bbababaaababbaababbaabab
8. bbaaababbaabaabaabbbbba ⇒ abaabbbbbabaaababbaabab
9. bbabaaababbaababbaabbba ⇒ abaabaabaabbbbbbbaaabab
10. bbababaaababbaababbaababbaabab ⇒ abaabaabaabaabaabbbbbbbbba
11. abaabaabaabaabaabaabaabbbbbbbbba ⇒ bbabababaaababbaababbaababbaabab
12. bbaaababbaabaabaabaabaabbbbbbba ⇒ abaabbbbbababaaababbaababbaabab
13. bbabaaababbaababbaabaabaabbbbba ⇒ abaabaabaabbbbbbbabaaababbaabab
14. bbababaaababbaababbaababbaabbba ⇒ abaabaabaabaabaabbbbbbbbbaaabab
15. bbabababaaababbaababbaababbaababbaabab ⇒ abaabaabaabaabaabaabaabbbbbbbbbbba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ba, [2/1] ab, [2/2] bb, [2/3] aa
Length 3:[3/0] aba, [3/1] bba, [3/2] baa, [3/3] aab, [3/4] bab, [3/5] bbb, [3/6] abb
Length 4:[4/0] baab, [4/1] aaba, [4/2] abaa, [4/3] abab, [4/4] bbaa, [4/5] bbbb, [4/6] bbba
Length 5:[5/0] baaba, [5/1] abaab, [5/2] aabab, [5/3] babba, [5/4] bbaab, [5/5] ababb, [5/6] abbaa
Length 6:[6/0] abaaba, [6/1] babbaa, [6/2] ababba, [6/3] abbaab, [6/4] baabab, [6/5] aababb, [6/6] baabaa
Length 7:[7/0] babbaab, [7/1] ababbaa, [7/2] aababba, [7/3] baabaab, [7/4] abaabaa, [7/5] bbaabab, [7/6] abbaaba

Considering [length 2 / frequency 0] ba=c.

Step 2

Rewriting system is complete. See a, b | abaabab=bba.