#2308 ⟨a, b | abaabab=abb⟩

Quick links

Presentation has sum-of-sides 10
Infinite non-cancellative non-commutative monoid
Not left cancellative, because left multiplication by a is not injective:
- a ⋅ ba(ab)² = ab² and a ⋅ b² = ab², however ba(ab)² ≠ b²
Not right cancellative, because right multiplication by b is not injective:
- (aba)² ⋅ b = ab² and ab ⋅ b = ab², however (aba)² ≠ ab
Enveloping group is isomorphic to ℤ

Format:	Pretty Plain
Word to reduce:
	Tips: Lowercase letters stand for generators. Spaces are ignored. Numbers repeat the previous letter, e.g. `b90`.
Reduction strategy:	Leftmost Rightmost
Path to normal form:	1 1

Auxiliary generators:
1. c = abb
Reduction order:
- Left-to-right recursive path with deg(a) = 0; deg(c) = deg(b) = 1, c < b
Certificate: derivations of all rewriting rules from the defining relations.

# ab:abaabab=abb a/cb abb=c magic:0
abb=c
cbb=caabc
caabab=cb
abaabc=cb
abaabab=c
cbaabc=caabcb
cbaabab=caabc

Up:	Monoids with two generators and one relation
Prev:	#2307 ⟨a, b \| abaabab=aba⟩
Next:	#2309 ⟨a, b \| abaabab=baa⟩