Morphocompletion for #2300 ⟨a, b | abaaaba=aab

Solved by morph:4/0,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaaba ⇒ aab
2. aabaaba ⇒ abaaaab
3. aaababaa ⇒ abaaaaab
4. ababaaaaab ⇒ aabbaa
5. abaabaaaab ⇒ aababa
6. abaaaabaaab ⇒ aaababa
7. abaaaaababa ⇒ aaabaab
8. aabbaaaba ⇒ aabab
9. aababaaba ⇒ aabbaaaab
10. aababbaaaba ⇒ aababab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aba, [3/1] aab, [3/2] aaa, [3/3] baa
Length 4:[4/0] aaba, [4/1] abaa, [4/2] aaab, [4/3] baaa
Length 5:[5/0] aaaba, [5/1] abaaa, [5/2] aabab, [5/3] ababa
Length 6:[6/0] abaaba, [6/1] baaaba, [6/2] abaaaa, [6/3] aababa

Considering [length 4 / frequency 0] aaba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: wordLimit

#Rule
1. cca ⇒ ac
2. abaca ⇒ c
3. cba ⇒ abccc
4. aab ⇒ abac
5. acb ⇒ abcccccccc
6. cab ⇒ abcccc
7. ababaccccc ⇒ cb
8. cbbac ⇒ abcccb
9. cbbab ⇒ cbbbac
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ab, [2/1] cb, [2/2] ba, [2/3] cc, [2/4] ca, [2/5] ac, [2/6] bb
Length 3:[3/0] aba, [3/1] cbb, [3/2] bac, [3/3] ccc, [3/4] bab, [3/5] bba, [3/6] aca
Length 4:[4/0] cbba, [4/1] abac, [4/2] cccc, [4/3] bbab, [4/4] abab, [4/5] bbac, [4/6] baca
Length 5:[5/0] ababa, [5/1] ccccc, [5/2] babac, [5/3] abacc, [5/4] baccc, [5/5] acccc, [5/6] cbbba

Considering [length 2 / frequency 0] ab=d.

Step 3

Rewriting system is complete. See a, b | abaaaba=aab.