Morphocompletion for #2292 ⟨a, b | abaaaab=aab⟩

Solved by morph:5/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abaaaab ⇒ aab
2. abaaaaab ⇒ aaab
3. abaaaaaab ⇒ aaaab
4. abaaaaaaab ⇒ aaaaab
5. abaaaaaaaab ⇒ aaaaaab
6. abaaaaaaaaab ⇒ aaaaaaab
7. abaaaaaaaaaab ⇒ aaaaaaaab
8. abaaaaaaaaaaab ⇒ aaaaaaaaab
9. abaaaaaaaaaaaab ⇒ aaaaaaaaaab
10. abaaaaaaaaaaaaab ⇒ aaaaaaaaaaab
11. abaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaab
12. abaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaab
13. abaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaab
14. abaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaab
15. abaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaab
16. abaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaab
17. abaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaab
18. abaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaab
19. abaaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaab
20. abaaaaaaaaaaaaaaaaaaaaaaab ⇒ aaaaaaaaaaaaaaaaaaaaab
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa250lf:250,rf:210,rp:20
[2/1]ab80lf:40,lp:20,ls:20,rf:20,rs:20,lprs:20,lsrs:20
[2/2]ba20lf:20
[3/0]aaa230lf:230,rf:190,rp:19
[3/1]aab40lf:20,ls:20,rf:20,rp:1,rs:20,re:1,lsrp:1,lsrs:20
[3/2]aba40lf:20,lp:20
[3/3]baa20lf:20
[4/0]aaaa210lf:210,rf:171,rp:18
[4/1]aaab40lf:20,ls:20,rf:19,rp:1,rs:19,re:1,lsrp:1,lsrs:19
[4/2]abaa40lf:20,lp:20
[4/3]baaa20lf:20
[5/0]aaaaa190lf:190,rf:153,rp:17,a:1
[5/1]aaaab40lf:20,ls:20,rf:18,rp:1,rs:18,re:1,lsrp:1,lsrs:18
[5/2]abaaa40lf:20,lp:20
[5/3]baaaa20lf:20
[6/0]aaaaaa171lf:171,rf:136,rp:16,a:2
[6/1]abaaaa40lf:20,lp:20
[6/2]aaaaab38lf:19,ls:19,rf:17,rp:1,rs:17,re:1,lsrp:1,lsrs:17,a:1
[6/3]baaaaa19lf:19,a:1
[6/4]baaaab2lf:1,ls:1
[7/0]aaaaaaa153lf:153,rf:120,rp:15,a:3
[7/1]abaaaaa38lf:19,lp:19,a:1
[7/2]aaaaaab36lf:18,ls:18,rf:16,rp:1,rs:16,re:1,lsrp:1,lsrs:16,a:2
[7/3]baaaaaa18lf:18,a:2
[7/4]baaaaab2lf:1,ls:1,a:1

Considering [length 5 / frequency 1] aaaab=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaaaab=aab⟩.