Morphocompletion for #2287 ⟨a, b | aabbbba=baa⟩

Solved by morph:5/2,4/0,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbbba ⇒ baa
2. aabbbbbaa ⇒ babaa
3. aabbbbbbaa ⇒ babbaa
4. aabbbbbabaa ⇒ bababaa
5. aabbbbbbbaa ⇒ babbbaa
6. aabbbbbabbaa ⇒ bababbaa
7. aabbbbbbabaa ⇒ babbabaa
...

Collecting factors up to length 7 / frequency 3:

[2/0]bb32lf:32,rf:5
[2/1]aa26lf:13,lp:7,ls:6,rf:7,rs:7,lprs:7,lsrs:6
[2/2]ba11lf:10,ls:1,rf:16,rp:7,lsrp:1
[3/0]bbb24lf:24,rf:1
[3/1]aab14lf:7,lp:7
[3/2]baa12lf:6,ls:6,rf:7,rp:1,rs:7,re:1,lsrs:6
[4/0]bbbb17lf:17
[4/1]aabb14lf:7,lp:7
[4/2]bbba8lf:7,ls:1,rf:1
[5/0]aabbb14lf:7,lp:7
[5/1]bbbbb10lf:10,a:1
[5/2]bbbba8lf:7,ls:1
[6/0]aabbbb14lf:7,lp:7
[6/1]bbbbba6lf:6,a:1
[6/2]abbbbb6lf:6,a:1

Considering [length 5 / frequency 2] bbbba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. baa ⇒ aac
2. bca ⇒ cac
3. babaca ⇒ aabcca
4. aacccc ⇒ ca
5. babacca ⇒ aabccca
6. bcbaca ⇒ cabcca
7. babbaca ⇒ aabbcca
8. bbbba ⇒ c
9. aacacccc ⇒ baca
10. babaccca ⇒ aabcccca
11. bcbacca ⇒ cabccca
12. bababcca ⇒ aabcbcca
13. babbacca ⇒ aabbccca
14. bcbbaca ⇒ cabbcca
15. aaccacccc ⇒ bbaca
16. cacacccc ⇒ bcca
17. bcbaccca ⇒ cabcccca
18. aacccbcca ⇒ cbaca
19. bcbabcca ⇒ cabcbcca
20. caccacccc ⇒ bbcca
...

Collecting factors up to length 6 / frequency 5:

[2/0]cc34lf:29,ls:5,rf:20,a:3
[2/1]ca34lf:19,lp:2,ls:13,rf:23,rp:7,rs:17,re:1,lsrp:15,lprs:2,lsrs:12,a:3
[2/2]ba27lf:19,lp:7,ls:1,rf:3,rp:1,a:1
[2/3]ac19lf:19,rf:5,rs:2,a:2
[2/4]bc15lf:9,lp:6,rf:15,rp:1,a:4
[3/0]ccc18lf:13,ls:5,rf:7,a:3
[3/1]cca18lf:10,ls:8,rf:13,rs:13,lsrs:7,a:6
[3/2]bab14lf:8,lp:6,a:8
[3/3]acc13lf:13,a:3
[3/4]bcb10lf:5,lp:5,rf:2,a:9
[4/0]cccc10lf:5,ls:5,rf:2,a:3
[4/1]bcba8lf:4,lp:4,a:9
[4/2]accc8lf:8,a:3
[4/3]baba8lf:4,lp:4,a:8
[4/4]baca8lf:4,ls:4,rf:3,rp:1,rs:3,re:1,a:5
[5/0]acccc10lf:5,ls:5,a:3
[5/1]bcbac6lf:3,lp:3,a:9
[5/2]babac6lf:3,lp:3,a:8
[5/3]bacca6lf:3,ls:3,a:11
[5/4]caccc4lf:4,a:5

Considering [length 4 / frequency 0] cccc=d.

Step 3

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ca ⇒ aad
2. baa ⇒ aac
3. cda ⇒ daad
4. dc ⇒ cd
5. cdda ⇒ ddaad
6. babada ⇒ aabdaad
7. aadadadad ⇒ da
8. cddda ⇒ dddaad
9. babadda ⇒ aabddaad
10. bcbada ⇒ aadbdaad
11. cccc ⇒ d
12. bbbba ⇒ c
13. aadaaddadad ⇒ bda
14. aaaaddadadad ⇒ bada
15. cdddda ⇒ ddddaad
16. bcbadda ⇒ aadbddaad
17. aadadadacd ⇒ dac
18. cddddda ⇒ dddddaad
19. aacccbdaad ⇒ cbada
20. aadadadaccd ⇒ dacc
...

Collecting factors up to length 6 / frequency 5:

[2/0]da34lf:25,ls:9,rf:15,rp:4,rs:4,re:1,lsrp:1,a:6
[2/1]ad27lf:23,ls:4,rf:14,rs:10,a:5
[2/2]aa18lf:11,lp:6,ls:1,rf:15,rp:6,lsrp:10,a:3
[2/3]cd14lf:7,lp:5,ls:2,rf:1,rp:1,rs:1,re:1,a:4
[2/4]dd14lf:14,rf:12,rp:4,a:8
[3/0]ada17lf:15,ls:2,rf:2,rs:2,a:6
[3/1]dad15lf:12,ls:3,a:6
[3/2]dda14lf:8,ls:6,rf:6,rp:1,lsrp:1,a:8
[3/3]aad12lf:7,lp:4,ls:1,rf:12,rp:3,rs:10,re:1,a:5
[3/4]cdd8lf:4,lp:4,a:8
[4/0]adad13lf:10,ls:3,a:6
[4/1]dada9lf:9,a:6
[4/2]aada8lf:4,lp:4,a:6
[4/3]cddd6lf:3,lp:3,a:9
[4/4]ddda6lf:3,ls:3,rf:3,rp:1,lsrp:1,a:9
[5/0]dadad10lf:7,ls:3,a:6
[5/1]adada7lf:7,a:6
[5/2]aadad6lf:3,lp:3,a:6
[5/3]cdddd4lf:2,lp:2,a:13
[5/4]bcbad4lf:2,lp:2,a:36

Considering [length 2 / frequency 0] da=e.

Step 4

Rewriting system is complete. See ⟨a, b | aabbbba=baa⟩.