Morphocompletion for #2270 ⟨a, b | aabbbaa=aab⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Reduction order:
- Left-to-right shortlex with a < b

Rewriting system is not complete: rulesLimit

#	Rule
1.	aabbbaa ⇒ aab
2.	aabbbbaa ⇒ aabb
3.	aababbbaa ⇒ aabab
4.	aabbbbbaa ⇒ aabbb
5.	aababbbbaa ⇒ aababb
6.	aabbabbbaa ⇒ aabbab
7.	aabbbbbbaa ⇒ aabbbb
	...

Collecting factors up to length 8 / frequency 7:

[2/0]	aa	28	`lf:14,lp:7,ls:7,rf:7,rp:7,lprp:7,lsrp:7`
[2/1]	bb	22	`lf:22,rf:8,rs:4`
[2/2]	ba	10	`lf:10,rf:3`
[2/3]	ab	10	`lf:10,rf:10,rs:3`
[3/0]	bbb	14	`lf:14,rf:3,rs:2`
[3/1]	baa	14	`lf:7,ls:7`
[3/2]	aab	14	`lf:7,lp:7,rf:7,rp:7,rs:1,re:1,lprp:7,lprs:1`
[3/3]	bba	8	`lf:8,rf:1`
[3/4]	abb	8	`lf:8,rf:5,rs:2`
[3/5]	bab	3	`lf:3,rf:3,rs:2,a:2`
[3/6]	aba	2	`lf:2,rf:2,a:2`
[4/0]	bbaa	14	`lf:7,ls:7`
[4/1]	aabb	10	`lf:5,lp:5,rf:4,rp:4,rs:1,re:1,lprp:4,lprs:1`
[4/2]	bbbb	7	`lf:7,rf:1,rs:1,a:1`
[4/3]	bbba	7	`lf:7`
[4/4]	abbb	7	`lf:7,rf:2,rs:1`
[4/5]	aaba	4	`lf:2,lp:2,rf:2,rp:2,lprp:2,a:2`
[4/6]	babb	3	`lf:3,rf:1,rs:1,a:2`
[5/0]	bbbaa	14	`lf:7,ls:7`
[5/1]	aabbb	8	`lf:4,lp:4,rf:2,rp:2,rs:1,re:1,lprp:2,lprs:1`
[5/2]	bbbba	4	`lf:4,a:1`
[5/3]	abbbb	4	`lf:4,rf:1,rs:1,a:1`
[5/4]	aabab	4	`lf:2,lp:2,rf:2,rp:2,rs:1,re:1,lprp:2,lprs:1,a:2`
[5/5]	bbbbb	3	`lf:3,a:3`
[5/6]	babbb	3	`lf:3,a:2`
[6/0]	bbbbaa	8	`lf:4,ls:4,a:1`
[6/1]	abbbaa	6	`lf:3,ls:3`
[6/2]	aabbbb	6	`lf:3,lp:3,rf:1,rp:1,rs:1,re:1,lprp:1,lprs:1,a:1`
[6/3]	aababb	4	`lf:2,lp:2,rf:1,rp:1,rs:1,re:1,lprp:1,lprs:1,a:2`
[6/4]	bbbbba	2	`lf:2,a:3`
[6/5]	babbba	2	`lf:2,a:2`
[6/6]	abbbbb	2	`lf:2,a:3`
[7/0]	bbbbbaa	4	`lf:2,ls:2,a:3`
[7/1]	babbbaa	4	`lf:2,ls:2,a:2`
[7/2]	abbbbaa	4	`lf:2,ls:2,a:1`
[7/3]	aabbbbb	4	`lf:2,lp:2,a:3`
[7/4]	aababbb	4	`lf:2,lp:2,a:2`
[7/5]	aabbbba	2	`lf:1,lp:1,a:1`
[7/6]	aabbabb	2	`lf:1,lp:1,a:5`

Considering [length 5 / frequency 0] bbbaa=c.

Step 2

Auxiliary generators:
1. c = bbbaa
Reduction order:
- Left-to-right shortlex with a < c < b

Rewriting system is complete. See ⟨a, b | aabbbaa=aab⟩.