Morphocompletion for #2270 ⟨a, b | aabbbaa=aab⟩

Back:⟨a, b | aabbbaa=aab⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbbaa ⇒ aab
2. aabbbbaa ⇒ aabb
3. aababbbaa ⇒ aabab
4. aabbbbbaa ⇒ aabbb
5. aababbbbaa ⇒ aababb
6. aabbabbbaa ⇒ aabbab
7. aabbbbbbaa ⇒ aabbbb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] bb, [2/2] ba, [2/3] ab
Length 3:[3/0] bbb, [3/1] baa, [3/2] aab, [3/3] bba, [3/4] abb, [3/5] bab, [3/6] aba
Length 4:[4/0] bbaa, [4/1] aabb, [4/2] bbbb, [4/3] bbba, [4/4] abbb, [4/5] aaba, [4/6] babb
Length 5:[5/0] bbbaa, [5/1] aabbb, [5/2] bbbba, [5/3] abbbb, [5/4] aabab, [5/5] bbbbb, [5/6] babbb
Length 6:[6/0] bbbbaa, [6/1] abbbaa, [6/2] aabbbb, [6/3] aababb, [6/4] bbbbba, [6/5] babbba, [6/6] abbbbb
Length 7:[7/0] bbbbbaa, [7/1] babbbaa, [7/2] abbbbaa, [7/3] aabbbbb, [7/4] aababbb, [7/5] aabbbba, [7/6] aabbabb

Considering [length 5 / frequency 0] bbbaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbbaa=aab⟩.